如何使用node和mongodb查找?

its*_* me 1 node.js express

下面的数据存储在我的收藏中

[
{ "_id" : ObjectId("53d9feff55d6b4dd1171dd9e"),"name":"John", "rank":1, "year":1998 ,"class":"a" ,"total":"1128" },
{ "_id" : ObjectId("feff553d95d6b4dd19e171dd"),"name":"Sherif", "rank":1, "year":1999 ,"class":"b" ,"total":"1163"},
{ "_id" : ObjectId("9fef53dd6b4dd1171f55dd9e"),"name":"shravan", "rank":1, "year":2000 ,"class":"b" ,"total":"1113"},
{ "_id" : ObjectId("117153d9fef6b4dddd9ef55d"),"name":"aneesh", "rank":1, "year":2001 ,"class":"d" ,"total":"1145"},
{ "_id" : ObjectId("dd9e53feff55d6b4dd1171d9"),"name":"abdul", "rank":1, "year":1997 ,"class":"a" ,"total":"1100"},
]
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我写了api for find,[{ "name":"John", "rank":1, "year":1998 },{ "name":"Sherif", "rank":1, "year":1999 }]这是我从req.body得到的数据,我在这里作为查询提到

router.post('/users',function(req,res){
  var query =[{ "name":"John", "rank":1, "year":1998 },{ "name":"Sherif", "rank":1, "year":1999 }]
  User.find(query, function(err, result) {
    if (err) throw err;
    console.log(result);
    res.json(result)

  });
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我期望这个res.json应该只返回这两个文件

[
{ "_id" : ObjectId("53d9feff55d6b4dd1171dd9e"),"name":"John", "rank":1, "year":1998 ,"class":"a" ,"total":"1128" },
{ "_id" : ObjectId("feff553d95d6b4dd19e171dd"),"name":"Sherif", "rank":1, "year":1999 ,"class":"b" ,"total":"1163"}]
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在mongodb中,我们可以这样写

db.users.find({rank:1, name:{$in:["John","Sherif"]}, year:{$in:[1998,1999]}})
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我想在nodejs中解决,表达是因为根据请求我们需要找到帮助我

小智 5

尝试使用mongoose $or运算符

var query = {
  $or : [
    {
      "name":"John", 
      "rank":1,
      "year":1998 
    },
    {
      "name":"Sherif",
      "rank":1, "year":1999 
    }
  ]
}
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