以编程方式通过whatsapp发送消息

Question

我正在尝试通过Whatsapp以编程方式发送消息,除了用户需要单击发送按钮之外,代码仍可正常工作.我需要应用程序来完成所有事情(所有用户交互).一种方法如下.

转到菜单按钮>设置>聊天.并选中"输入发送选项"

这是我正在使用的代码:

protected void sendwts(){
    String smsNumber = "2126123456789"; // E164 format without '+' sign
    Intent sendIntent = new Intent(Intent.ACTION_SEND);
    //  Intent sendIntent = new Intent(Intent.ACTION_SENDTO);
    sendIntent.setType("text/plain");
    sendIntent.putExtra(Intent.EXTRA_TEXT, "test \n");
    sendIntent.putExtra("jid", smsNumber + "@s.whatsapp.net"); //phone number without "+" prefix
    sendIntent.setPackage("com.whatsapp");

    startActivity(sendIntent);
}

谢谢

Answer 1

您只能使用Android 的辅助功能API执行此操作.

这个想法很简单,你实际上会让Android执行点击Whatsapp的发送按钮.

所以流程将是:

1. 发送常规消息(具有您当前使用的意图),并在消息内容的末尾添加后缀,例如" Sent by MY_APP".
2. 一旦文本在那里,您的可访问性服务将被通知EditTextwhatsapp的填充.
3. 如果EditTextwhatsapp 上有后缀,则您的辅助功能服务将单击发送按钮.(这是为了避免在用户自然键入常规消息时执行操作).

这是一个例子(如果你想让它更具限制性,你可以调整它):

public class WhatsappAccessibilityService extends AccessibilityService {

    @Override
    public void onAccessibilityEvent (AccessibilityEvent event) {
        if (getRootInActiveWindow () == null) {
            return;
        }

        AccessibilityNodeInfoCompat rootInActiveWindow = AccessibilityNodeInfoCompat.wrap (getRootInActiveWindow ());

        // Whatsapp Message EditText id
        List<AccessibilityNodeInfoCompat> messageNodeList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.whatsapp:id/entry");
        if (messageNodeList == null || messageNodeList.isEmpty ()) {
            return;
        }

        // check if the whatsapp message EditText field is filled with text and ending with your suffix (explanation above)
        AccessibilityNodeInfoCompat messageField = messageNodeList.get (0);
        if (messageField.getText () == null || messageField.getText ().length () == 0 
            || !messageField.getText ().toString ().endsWith (getApplicationContext ().getString (R.string.whatsapp_suffix))) { // So your service doesn't process any message, but the ones ending your apps suffix
            return;
        }

        // Whatsapp send button id
        List<AccessibilityNodeInfoCompat> sendMessageNodeInfoList = rootInActiveWindow.findAccessibilityNodeInfosByViewId ("com.whatsapp:id/send");
        if (sendMessageNodeInfoList == null || sendMessageNodeInfoList.isEmpty ()) {
            return;
        }

        AccessibilityNodeInfoCompat sendMessageButton = sendMessageNodeInfoList.get (0);
        if (!sendMessageButton.isVisibleToUser ()) {
            return;
        }

        // Now fire a click on the send button
        sendMessageButton.performAction (AccessibilityNodeInfo.ACTION_CLICK);

        // Now go back to your app by clicking on the Android back button twice: 
        // First one to leave the conversation screen 
        // Second one to leave whatsapp
        try {
            Thread.sleep (500); // hack for certain devices in which the immediate back click is too fast to handle
            performGlobalAction (GLOBAL_ACTION_BACK);
            Thread.sleep (500);  // same hack as above
        } catch (InterruptedException ignored) {}
        performGlobalAction (GLOBAL_ACTION_BACK);
    }
}

然后在res -> xml -> whatsapp_service.xml以下位置创建其定义

<?xml version="1.0" encoding="utf-8"?>
<accessibility-service
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:accessibilityEventTypes="typeWindowContentChanged"
    android:packageNames="com.whatsapp"
    android:accessibilityFeedbackType="feedbackSpoken"
    android:notificationTimeout="100"
    android:canRetrieveWindowContent="true"/>

然后在清单中声明它:

<service
    android:name=".services.WhatsappAccessibilityService"
    android:label="Accessibility Service"
   android:permission="android.permission.BIND_ACCESSIBILITY_SERVICE">
    <meta-data
        android:name="android.accessibilityservice"
        android:resource="@xml/whatsapp_service"/>

    <intent-filter>
        <action android:name="android.accessibilityservice.AccessibilityService"/>
    </intent-filter>
</service>

最后,是检查是否为您的应用启用了辅助功能服务,如果没有,则将用户重定向到设置:

private boolean isAccessibilityOn (Context context, Class<? extends AccessibilityService> clazz) {
    int accessibilityEnabled = 0;
    final String service = context.getPackageName () + "/" + clazz.getCanonicalName ();
    try {
        accessibilityEnabled = Settings.Secure.getInt (context.getApplicationContext ().getContentResolver (), Settings.Secure.ACCESSIBILITY_ENABLED);
    } catch (Settings.SettingNotFoundException ignored) {  }

    TextUtils.SimpleStringSplitter colonSplitter = new TextUtils.SimpleStringSplitter (":");

    if (accessibilityEnabled == 1) {
        String settingValue = Settings.Secure.getString (context.getApplicationContext ().getContentResolver (), Settings.Secure.ENABLED_ACCESSIBILITY_SERVICES);
        if (settingValue != null) {
            colonSplitter.setString (settingValue);
            while (colonSplitter.hasNext ()) {
                String accessibilityService = colonSplitter.next ();

                if (accessibilityService.equalsIgnoreCase (service)) {
                    return true;
                }
            }
        }
    }

    return false;
}

你打电话给谁:

if (!isAccessibilityOn (context, WhatsappAccessibilityService.class)) {
    Intent intent = new Intent (Settings.ACTION_ACCESSIBILITY_SETTINGS);
    context.startActivity (intent);
}

这完全取决于解决方案的技术方面.

现在,道德问题是"你应该这样做吗？" ,我相信答案很清楚:

除非您针对残障人士(这是Accessibility API的目的),否则您可能不应该这样做.