pro*_*els 5 python artificial-intelligence machine-learning neural-network tensorflow
我正在使用带有numpy和tensorflow的多层感知器进行二进制分类。
输入矩阵的形状= (9578,18)
标签的形状为=(9578,1)
这是代码:
#preprocessing
input = np.loadtxt("input.csv", delimiter=",", ndmin=2).astype(np.float32)
labels = np.loadtxt("label.csv", delimiter=",", ndmin=2).astype(np.float32)
train_size = 0.9
train_cnt = floor(inp.shape[0] * train_size)
x_train = input[0:train_cnt]
y_train = labels[0:train_cnt]
x_test = input[train_cnt:]
y_test = labels[train_cnt:]
#defining parameters
learning_rate = 0.01
training_epochs = 100
batch_size = 50
n_classes = labels.shape[1]
n_samples = 9578
n_inputs = input.shape[1]
n_hidden_1 = 20
n_hidden_2 = 20
def multilayer_network(X,weights,biases,keep_prob):
'''
X: Placeholder for data inputs
weights: dictionary of weights
biases: dictionary of bias values
'''
#first hidden layer with sigmoid activation
# sigmoid(X*W+b)
layer_1 = tf.add(tf.matmul(X,weights['h1']),biases['h1'])
layer_1 = tf.nn.sigmoid(layer_1)
layer_1 = tf.nn.dropout(layer_1,keep_prob)
#second hidden layer
layer_2 = tf.add(tf.matmul(layer_1,weights['h2']),biases['h2'])
layer_2 = tf.nn.sigmoid(layer_2)
layer_2 = tf.nn.dropout(layer_2,keep_prob)
#output layer
out_layer = tf.matmul(layer_2,weights['out']) + biases['out']
return out_layer
#defining the weights and biases dictionary
weights = {
'h1': tf.Variable(tf.random_normal([n_inputs,n_hidden_1])),
'h2': tf.Variable(tf.random_normal([n_hidden_1,n_hidden_2])),
'out': tf.Variable(tf.random_normal([n_hidden_2,n_classes]))
}
biases = {
'h1': tf.Variable(tf.random_normal([n_hidden_1])),
'h2': tf.Variable(tf.random_normal([n_hidden_2])),
'out': tf.Variable(tf.random_normal([n_classes]))
}
keep_prob = tf.placeholder("float")
X = tf.placeholder(tf.float32,[None,n_inputs])
Y = tf.placeholder(tf.float32,[None,n_classes])
predictions = multilayer_network(X,weights,biases,keep_prob)
#cost function(loss) and optimizer function
cost = tf.reduce_mean(tf.nn.sigmoid_cross_entropy_with_logits(logits=predictions,labels=Y))
optimizer = tf.train.AdamOptimizer(learning_rate=learning_rate).minimize(cost)
#running the session
init = tf.global_variables_initializer()
with tf.Session() as sess:
sess.run(init)
#for loop
for epoch in range(training_epochs):
avg_cost = 0.0
total_batch = int(len(x_train) / batch_size)
x_batches = np.array_split(x_train, total_batch)
y_batches = np.array_split(y_train, total_batch)
for i in range(total_batch):
batch_x, batch_y = x_batches[i], y_batches[i]
_, c = sess.run([optimizer, cost],
feed_dict={
X: batch_x,
Y: batch_y,
keep_prob: 0.8
})
avg_cost += c / total_batch
print("Epoch:", '%04d' % (epoch+1), "cost=", \
"{:.9f}".format(avg_cost))
print("Model has completed {} epochs of training".format(training_epochs))
correct_prediction = tf.equal(tf.argmax(predictions, 1), tf.argmax(Y, 1))
accuracy = tf.reduce_mean(tf.cast(correct_prediction, "float"))
print("Accuracy:", accuracy.eval({X: x_test, Y: y_test,keep_probs=1.0}))
Run Code Online (Sandbox Code Playgroud)
在将我的模型运行了100个时间段后,成本在每个时间段后都会降低,这意味着网络可以正常运行,但是每次的精度都为1.0,因此我不知道为什么我是个初学者神经网络及其功能。因此,任何帮助将不胜感激。谢谢!
编辑: 我尝试在每个时期后检查预测矩阵,并且每次都获得全零。我在带有循环的for循环中使用了以下代码来检查预测矩阵:
for epoch in range(training_epochs):
avg_cost = 0.0
total_batch = int(len(x_train) / batch_size)
x_batches = np.array_split(x_train, total_batch)
y_batches = np.array_split(y_train, total_batch)
for i in range(total_batch):
batch_x, batch_y = x_batches[i], y_batches[i]
_, c,p = sess.run([optimizer, cost,predictions],
feed_dict={
X: batch_x,
Y: batch_y,
keep_prob: 0.8
})
avg_cost += c / total_batch
print("Epoch:", '%04d' % (epoch+1), "cost=", \
"{:.9f}".format(avg_cost))
y_pred = sess.run(tf.argmax(predictions, 1), feed_dict={X: x_test,keep_prob:1.0})
y_true = sess.run(tf.argmax(y_test, 1))
acc = sess.run(accuracy, feed_dict={X: x_test, Y: y_test,keep_prob:1.0})
print('Accuracy:', acc)
print ('---------------')
print(y_pred, y_true)
print("Model has completed {} epochs of training".format(training_epochs))
Run Code Online (Sandbox Code Playgroud)
这是1个纪元的输出:
Epoch: 0001 cost= 0.543714217
Accuracy: 1.0
---------------
[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0] [0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
Run Code Online (Sandbox Code Playgroud)
您没有针对预测调用 sess.run 。这意味着它当前是代表张量流图的变量,而不是预测的值。
将您的替换_, c = sess.run([optimizer, cost], ...)为_, c, p = sess.run([optimizer, cost, predictions], ...). 然后correct_prediction对p得到的值进行计算。同样,真值是batch_y,因为您的Y变量也是张量流图对象。因此,您现在将使用 numpy 变量,因此应该使用而不是 来argmax完成调用。我相信这应该能解决问题。nptf
如果您想在张量流中执行此操作,请将正确的预测和准确性计算移至计算成本的位置,并将 sess.run 行更改为:_, c, a = sess.run([optimizer, cost, accuracy], ...)
为了解释为什么你得到 100%,你有一行correct_prediction = tf.equal(tf.argmax(predictions, 1), tf.argmax(Y, 1)),其中 和predictions都是Y张量流图变量。您可以将它们视为调用时值将流经的包装器sess.run()。因此,当您打印准确性时,您正在将张量流图操作与张量流图操作进行比较,并且我猜后端将它们视为始终相等。
编辑:下面提到的两种不同方法的示例代码。不能 100% 确定它有效,因为我无法轻松测试它(我没有你的数据),但它应该是这样的。
第一种方法:
_, c, p = sess.run([optimizer, cost, predictions], ...)
.
.
.
correct_prediction = np.equal(np.argmax(p, axis=1), np.argmax(batch_y, axis=1))
accuracy = np.mean(correct_prediction)
Run Code Online (Sandbox Code Playgroud)
第二种方法:
cost = tf.reduce_mean(tf.nn.sigmoid_cross_entropy_with_logits(logits=predictions,labels=Y))
correct_prediction = tf.equal(tf.argmax(predictions, 1), tf.argmax(Y, 1))
accuracy = tf.reduce_mean(tf.cast(correct_prediction, tf.float32))
.
.
.
for i in range(total_batch):
batch_x, batch_y = x_batches[i], y_batches[i]
_, c, a = sess.run([optimizer, cost, accuracy],
feed_dict={
X: batch_x,
Y: batch_y,
keep_prob: 0.8
})
print(a)
Run Code Online (Sandbox Code Playgroud)
编辑2:虽然上述信息仍然正确,但还有另一个问题。当您仅预测一类时,使用交叉熵和准确性是没有意义的。如果你对长度为 1 的东西调用 argmax,那么你总是会得到 0,因为这是唯一存在的位置!准确性和交叉熵仅在基于类的预测的背景下才有意义,其中您的真值是跨类列表的独热向量。