从 DeepDiff 结果构建 python dict

Sri*_*esh 5 python dictionary deep-diff

我有一个 DeepDiff 结果,它是通过比较两个 JSON 文件获得的。我必须从 deepdiff 结果构建一个 python 字典,如下所示。

json1 = {"spark": {"ttl":3, "poll":34}}
json2 = {"spark": {"ttl":3, "poll":34, "toll":23}, "cion": 34}

deepdiffresult = {'dictionary_item_added': {"root['spark']['toll']", "root['cion']"}}

expecteddict = {"spark" : {"toll":23}, "cion":34}
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如何做到这一点?

Jam*_*mes 4

可能有更好的方法来做到这一点。但是您可以解析返回的字符串并将一个新字典与您想要的结果链接在一起。

json1 = {"spark": {"ttl":3, "poll":34}}
json2 = {"spark": {"ttl":3, "poll":34, "toll":23}, "cion": 34}
deepdiffresult = {'dictionary_item_added': {"root['spark']['toll']", "root['cion']"}}
added = deepdiffresult['dictionary_item_added']

def convert(s, j):
    s = s.replace('root','')
    s = s.replace('[','')
    s = s.replace("'",'')
    keys = s.split(']')[:-1]
    d = {}
    for k in reversed(keys):
        if not d:
            d[k] = None
        else:
            d = {k: d}
    v = None
    v_ref = d
    for i, k in enumerate(keys, 1):
        if not v:
            v = j.get(k)
        else:
            v = v.get(k)
        if i<len(keys):
            v_ref = v_ref.get(k)
    v_ref[k] = v
    return d

added_dict = {}
for added_str in added:
    added_dict.update(convert(added_str, json2))

added_dict
#returns:
{'cion': 34, 'spark': {'toll': 23}}
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