如何从 include_tasks 传回结果

Question

昨天开始学习ansible，所以我相信我可能会在这里冒着XY问题的风险，但仍然\xe2\x80\xa6

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主要的yml：

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- hosts: localhost\n\n  vars_files:\n    [ "users.yml" ]\n  tasks:\n    - name: manage instances\n      #include_tasks: create_instance.yml\n      include_tasks: inhabit_instance.yml\n      with_dict: "{{users}}"\n      register: res\n    - name: print\n      debug: msg="{{res.results}}"\n

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inhabit_instance.yml：

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- name: Get instance info for {{ item.key }}\n  ec2_instance_facts:\n    profile: henryaws\n    filters:\n      "tag:name": "{{item.key}}"\n      instance-state-name: running\n  register: ec2\n- name: print\n  debug:\n    msg: "IP: {{ec2.instances.0.public_ip_address}}"\n

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这就是我想要的顶层 IP。还没有立即找到有关包含块的返回值的任何信息\xe2\x80\xa6

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Answer 1

好吧，我找到了一些适合我的方法，也许它甚至是规范的？

主要.yml：

- hosts: localhost

  vars_files:
    [ "users.yml" ]
  vars: 
    ec_results: {}
  tasks:
    - name: manage instances
      #include_tasks: create_instance.yml
      include_tasks: inhabit_instance.yml
      with_dict: "{{users}}"
      register: res

inhabit_instance.yml：

- name: Get instance info for {{ item.key }}
  ec2_instance_facts:
    profile: henryaws
    filters:
      "tag:name": "{{item.key}}"
      instance-state-name: running
  register: ec2
- name: update
  set_fact:
    ec_results: "{{ ec_results|combine({ item.key: ec2.instances.0.public_ip_address }) }}"