我试图使用这个获取我专栏中的最后一条记录
ObjectRes.query.order_by('-id').first()
Run Code Online (Sandbox Code Playgroud)
但结果是:无
我尝试使用所有其他查询,唯一有效的是
obj = ObjectRes.query.all()
return str(obj[-1].id)
Run Code Online (Sandbox Code Playgroud)
查询太繁重,需要在 Pythonanywhere 上使用更轻量级的查询。谢谢
Columns in SQLAlchemy models have methods attached to produce this behaviour. To order by ID descending, do this:
descending = Object.query.order_by(Object.id.desc())
last_item = descending.first()
Run Code Online (Sandbox Code Playgroud)
Specifying Object.field is the clearest syntax for choosing a field to order by, and all columns / model attributes should support .desc() or .asc()
You can of course do this in a one liner as well:
last_item = Object.query.order_by(Object.id.desc()).first()
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4866 次 |
| 最近记录: |