Alo*_*pex 5 c fork ipc parent-child child-process
我应该将斐波纳契系列的前12个术语的总和从子进程返回到父进程,但是377父进来了30976.
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>
int main(int argc, char *argv[])
{
pid_t childpid;
int i, fib_sum=0, fib1=1, fib2=1, temp, status;
childpid=fork();
if(childpid!=0)
{
wait(&status);
fprintf(stderr, "%d\n", status);
}
else
{
for(i=1; i<=12; i++)
{
temp=fib1;
fib_sum=fib1+fib2;
fib1=fib_sum;
fib2=temp;
}
fprintf(stderr, "%d\n", fib_sum);
return fib_sum;
}
}
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我究竟做错了什么?
我应该将斐波那契数列的前 12 项之和从子进程返回给父进程,但父进程得到的是 377,而是 30976。
进程退出状态的值有限,因此它不是在子进程和父进程之间传递值的最佳方式。
解决方案之一是使用管道传递计算值。
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>
int main(int argc, char *argv[])
{
pid_t childpid;
int i, fib_sum=0, fib1=1, fib2=1, temp, status;
int fd[2];
int val = 0;
// create pipe descriptors
pipe(fd);
childpid = fork();
if(childpid != 0) // parent
{
close(fd[1]);
// read the data (blocking operation)
read(fd[0], &val, sizeof(val));
printf("Parent received value: %d\n", val);
// close the read-descriptor
close(fd[0]);
}
else // child
{
// writing only, no need for read-descriptor:
close(fd[0]);
for(i=1; i<=12; i++)
{
temp = fib1;
fib_sum = fib1+fib2;
fib1 = fib_sum;
fib2 = temp;
}
// send the value on the write-descriptor:
write(fd[1], &fib_sum, sizeof(fib_sum));
printf("Child send value: %d\n", fib_sum);
// close the write descriptor:
close(fd[1]);
return fib_sum;
}
}
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测试:
Child send value: 377
Parent received value: 377
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