Laz*_*row 5 c++ macos dtrace system-calls dtruss
我最近决定学习更多关于系统编程的知识,并且觉得看看我的代码实际上在做什么是很有帮助的.
为此,我在C++中编写了一个简短的LinkedList类,并决定使用它来跟踪它dtruss(读取:dtrace).
我的期望是任何扩展堆的指令(例如使用new关键字或实例化LinkedList对象)都会调用mmap或sbrk/ break系统调用.此情况并非如此!
实际上,dtruss使用-s开关运行时,我看不到从我的函数内部调用任何系统调用LinkedList::Add!测试,我正在添加某些元素.
任何人都可以解释为什么我没有看到mmap/ sbrk在我的dtruss输出中的引用?
奖励积分,如果有人可以解释的目的mprotect和madvise.
我在下面包含了我的LinkedList类,main.cpp和dtruss输出.
谢谢!
dtruss输出
SYSCALL(args)        = return
Created new LinkedList
Created new LinkedList
Destroyed a LinkedList
open("/dev/dtracehelper\0", 0x2, 0xFFFFFFFFE3236D70)         = 3 0
ioctl(0x3, 0x80086804, 0x7FFEE3236CD0)       = 0 0
close(0x3)       = 0 0
access("/AppleInternal/XBS/.isChrooted\0", 0x0, 0x0)         = -1 Err#2
thread_selfid(0x0, 0x0, 0x0)         = 198178 0
bsdthread_register(0x7FFF5BAB5C50, 0x7FFF5BAB5C40, 0x2000)       = 1073742047 0
issetugid(0x0, 0x0, 0x0)         = 0 0
mprotect(0x10C9D0000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9D5000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9D6000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9DB000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9CE000, 0x88, 0x1)         = 0 0
mprotect(0x10C9DC000, 0x1000, 0x1)       = 0 0
mprotect(0x10C9CE000, 0x88, 0x3)         = 0 0
mprotect(0x10C9CE000, 0x88, 0x1)         = 0 0
getpid(0x0, 0x0, 0x0)        = 1698 0
stat64("/AppleInternal/XBS/.isChrooted\0", 0x7FFEE32362E8, 0x0)      = -1 Err#2
stat64("/AppleInternal\0", 0x7FFEE3236380, 0x0)      = -1 Err#2
csops(0x6A2, 0x7, 0x7FFEE3235E20)        = -1 Err#22
sysctl([CTL_KERN, 14, 1, 1698, 0, 0] (4), 0x7FFEE3235F68, 0x7FFEE3235F60, 0x0, 0x0)      = 0 0
csops(0x6A2, 0x7, 0x7FFEE3235710)        = -1 Err#22
getrlimit(0x1008, 0x7FFEE32374F0, 0x0)       = 0 0
fstat64(0x1, 0x7FFEE3237508, 0x0)        = 0 0
ioctl(0x1, 0x4004667A, 0x7FFEE3237554)       = 0 0
write_nocancel(0x1, "Created new LinkedList\n\0", 0x17)      = 23 0
write_nocancel(0x1, "Created new LinkedList\n\0", 0x17)      = 23 0
write_nocancel(0x1, "Destroyed a LinkedList\n\0", 0x17)      = 23 0
LinkedList.cpp
#include <iostream>
#include "LinkedList.h"
using namespace std;
LinkedList::LinkedList() {
    this->length = 0;
    this->head = NULL;
    this->tail = NULL;
    cout << "Created new LinkedList" << endl;
}
LinkedList::~LinkedList() {
    Node* curr;
    Node* temp;
    curr = this->head;
    while ( curr ) {
        temp = curr;
        curr = curr->next;
        delete temp;
    }
    cout << "Destroyed a LinkedList" << endl;
}
void LinkedList::Add(int v) {
    Node* n = new Node();
    n->val = v;
    n->next = NULL;
    if (!this->head) {
        this->head = n;
        this->tail = n;
    } else {
        this->tail->next = n;
        this->tail = n;
    }    
}
main.cpp中
#include <iostream>
#include "LinkedList.h"
using namespace std;
int main() {
    LinkedList l; // You should require a heap increase, right?
    LinkedList* ll = new LinkedList(); // Surely you require more heap!
    for (int i=0; i<1000; i++) 
        l.Add(i);
    return 0;
}
我发现 Mac OSsbrk/brk/break()不像大多数 UNIX/Linux 那样使用内存管理。基本上,它使用 Apple 从 NeXT 继承的 Mach 内核,因此内存调用mpadvise(2)将比.mprotect(2)sbrk()
来自 Jonathan Levin 的“Mac OS X 和 iOS 内部结构”:
因此,要解释内存分配,您需要了解标头mprotect(2)中的参数sys/mman.h。
#define PROT_NONE       0x00    /* [MC2] no permissions */
#define PROT_READ       0x01    /* [MC2] pages can be read */
#define PROT_WRITE      0x02    /* [MC2] pages can be written */
#define PROT_EXEC       0x04    /* [MC2] pages can be executed */
....
所以你的系统调用意味着:
mprotect(0x10C9D0000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9D5000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9D6000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9DB000, 0x1000, 0x0)       = 0 0
mprotect(0x10C9CE000, 0x88, 0x1)         = 0 0  <-- Allow reads starting at 0x10C9CE000 for 136 bytes
mprotect(0x10C9DC000, 0x1000, 0x1)       = 0 0
mprotect(0x10C9CE000, 0x88, 0x3)         = 0 0  <-- Allow reads and writes starting at 0x10C9CE000 for 136 bytes
mprotect(0x10C9CE000, 0x88, 0x1)         = 0 0
关于mmap(2),在 Linux 系统上它用于映射共享库的目标代码,但不用于malloc/free或new/delete。
参考:
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