Mik*_*dan 4 java reactive-programming project-reactor
Project Reactor 3.1.5.RELEASE
考虑一下:
Flux.range(0, 10)
.publishOn(Schedulers.parallel())
.subscribe(i -> LOG.info(i));
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我期望订阅者在多个线程中运行,但它只运行在一个:
2018-03-26 12:30:08.693 INFO 89770 --- [ parallel-1] d.a.Application : 0
2018-03-26 12:30:08.693 INFO 89770 --- [ parallel-1] d.a.Application : 1
2018-03-26 12:30:08.693 INFO 89770 --- [ parallel-1] d.a.Application : 2
2018-03-26 12:30:08.693 INFO 89770 --- [ parallel-1] d.a.Application : 3
2018-03-26 12:30:08.694 INFO 89770 --- [ parallel-1] d.a.Application : 4
2018-03-26 12:30:08.694 INFO 89770 --- [ parallel-1] d.a.Application : 5
2018-03-26 12:30:08.694 INFO 89770 --- [ parallel-1] d.a.Application : 6
2018-03-26 12:30:08.694 INFO 89770 --- [ parallel-1] d.a.Application : 7
2018-03-26 12:30:08.694 INFO 89770 --- [ parallel-1] d.a.Application : 8
2018-03-26 12:30:08.694 INFO 89770 --- [ parallel-1] d.a.Application : 9
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文档告诉我的期望是正确的(http://projectreactor.io/docs/core/release/reference/#threading).有人可以向我解释那里发生了什么吗?
aka*_*okd 14
反应流本质上是顺序的,publishOn只是告诉源在哪里一个接一个地发出每个值.您需要告诉流程并行通过parallel,然后通过runOn以下方式指定调度程序:
Flux.range(0, 10)
.parallel()
.runOn(Schedulers.parallel())
.doOnNext(i -> LOG.info(i))
.sequential()
.subscribe();
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