如何将十六进制转换为varchar(datetime)？

Question

我有日期时间导出是"CAST(0x0000987C00000000 AS DateTime)",但当我想将它恢复到datetime.It是一个NULL值.我怎样才能再次进入日期时间.

Answer 1

这看起来像SQL Server datetime格式.在内部,它存储为2个整数,前4个字节是自1900年1月1日以来的天数,第2个字节是自午夜以来的刻度数(每个刻度为1/300秒).

如果您需要在MySQL中使用它,您可以这样做

SELECT 
      CAST(
          '1900-01-01 00:00:00' + 
          INTERVAL CAST(CONV(substr(HEX(BinaryData),1,8), 16, 10)  AS SIGNED) DAY +
          INTERVAL CAST(CONV(substr(HEX(BinaryData),9,8), 16, 10)  AS SIGNED)* 10000/3 MICROSECOND
      AS DATETIME) AS converted_datetime
FROM
(
SELECT 0x0000987C00000000 AS BinaryData
UNION ALL
SELECT 0x00009E85013711EE AS BinaryData
) d

返回

converted_datetime
--------------------------
2006-11-17 00:00:00
2011-02-09 18:52:34.286667

(感谢Ted Hopp提供的拆分二进制数据的解决方案)

Answer 2

没有真正添加任何未说明但我用它来从上面的代码创建一个MySql函数.然后我可以使用RegEx查找和替换(在Notepad ++中)用sp_ConvertSQLServerDate(0xblahblahblah)替换CAST(0xblahblahblah AS DATETIME).

create function sp_ConvertSQLServerDate(dttm binary(16))
returns datetime
return CAST(
      '1900-01-01 00:00:00' + 
      INTERVAL CAST(CONV(substr(HEX(dttm),1,8), 16, 10)  AS SIGNED) DAY +
      INTERVAL CAST(CONV(substr(HEX(dttm),9,8), 16, 10)  AS SIGNED)* 10000/3 MICROSECOND
AS DATETIME);