Aam*_*ain 2 javascript regex ajax jquery
我有url,其中参数包含'&'字符..现在我必须做一个ajax调用,但服务器发送异常...所以解决方案是用%26替换'&'参数然后使呼叫...
例如..
url = http://localhost.com/?q=java&industry="IT&web"&location="New-york & Florida"
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结果必须是......
= http://localhost.com/?q=java&industry="IT%26web"&location="New-york %26 Florida"
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你必须使用:
query = encodeURIComponent (query);
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