将命令的输出结果存储到数组中

Question

我有bash命令输出的问题.我想将命令的结果保存到数组并将第一部分切换为[0]并将第二部分切换为[1]

result=$(findId PATTERN | tr -s " " | cut -d " " -f 1)

findID的输出是:

id errorcode nameOfProgramRunned

例:

12345 "compilation problem" fullScan.java
12346 "other problem" basicTest.java

我想保存id到array[0]和nameofProgramRunned到array[1]

主要问题是我想避免两次执行命令,因为结果可能不同.

当前代码:

#!/bin/sh
echo 'Enter error code:'
read errorLine

result=$(findID PATTERN | awk '{print $1}')

while read -r line
do

    dir="/proj/jobs/"$line"/screenlog.*"

    if [ -e $dir ]
    then
        if grep -qi "$errorLine" $dir  
        then    
            echo -e "\e[101m$line:\e[49m"       
            grep $dir -i -e "$errorLine"

        fi  
    fi
done <<<"$result"

我想将nameOfProgramRunned添加到最终的grep

我正在使用bash

Answer 1

针对开放长度数组进行编辑。

echo -e '12345\t"compilation problem"\tfullScan.java' | {
  IFS=$'\t' read -r -a FOO
  echo number: ${FOO[0]}
  echo string: ${FOO[1]}
  echo file: ${FOO[2]}
}

注意 IFS 被设置为制表符分隔符

还看一下

help read # bash built in help