javascript旋转数组元素

Question

大家好，我有这个任务：我有一个数组 [4,7,3,6,9] ，我必须制作一个这样的数组：

[4,7,3,6,9]
[9,4,7,3,6]
[6,9,4,7,3]
[3,6,9,4,7]
[7,3,6,9,4]

我必须制作一个程序，其中数组正在旋转，即使我向数组添加一个新项目，它也应该相应地改变。我是 JS 的新手，大约 1 周，这是我目前的尝试：

var numbers = [4, 7, 3, 6, 9];
console.log(numbers);
numbers[0] = 9; numbers[1] = 4; numbers[2] = 7; numbers[3] = 3; numbers[4] = 6;
console.log(numbers);
numbers[0] = 6; numbers[1] = 9; numbers[2] = 4; numbers[3] = 7; numbers[4] = 3;
console.log(numbers);
numbers[0] = 3; numbers[1] = 6; numbers[2] = 9; numbers[3] = 4; numbers[4] = 7;
console.log(numbers);
numbers[0] = 7; numbers[1] = 3; numbers[2] = 6; numbers[3] = 9; numbers[4] = 4;
console.log(numbers);

同样在我的脑海中，我有 .push、.splice 等。我不知道为什么，但我真的觉得 javascript 不适合我的大脑，哈哈：D

Answer 1

您可以弹出该值并取消移动它。

var array = [4, 7, 3, 6, 9],
    i = array.length;

while (i--) {
    console.log(array.join(' '));
    array.unshift(array.pop());
}
console.log(array.join(' '));