尝试这个:
解决方案1:
这是来自Ajons 的答案
SELECT k.COLUMN_NAME
FROM information_schema.table_constraints t
LEFT JOIN information_schema.key_column_usage k
USING(constraint_name,table_schema,table_name)
WHERE t.constraint_type='PRIMARY KEY'
AND t.table_schema=DATABASE()
AND t.table_name='owalog';
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解决方案2:
这是来自alexn
SHOW KEYS FROM tablename WHERE Key_name = 'PRIMARY'
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解决方案3:
SHOW INDEX FROM presort.final_conf_score_mld_run2
WHERE Key_name = 'PRIMARY';
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