end*_*hin 5 sql database oracle select count
我有一个像这样的Oracle数据库表,它记录了在扫描点扫描的项目.
ItemsScan
ItemScanId
ItemScanPoint
ItemType
ScanTime
我想返回ItemScanPoint以及在该ItemScanPoint上扫描特定ItemType的次数.
有点像..
SELECT ItemScanPoint,
(SELECT COUNT(*) WHERE ItemType = 1),
(SELECT COUNT(*) WHERE ItemType = 2)
FROM ItemsScan
Run Code Online (Sandbox Code Playgroud)
我怎么在oracle中这样做?
什么是最有效的方式?
rem*_*rel 13
SELECT ItemScanPoint,
SUM(CASE ItemType WHEN 1 THEN 1 ELSE 0 END) ,
SUM(CASE ItemType WHEN 2 THEN 1 ELSE 0 END)
FROM ItemsScan
GROUP BY ItemScanPoint
Run Code Online (Sandbox Code Playgroud)