我希望能够通过Servant作为响应主体来传输S3存储桶对象内容.
我遇到问题,因为Handler缺少MonadResource实例:
src/Servant/Streaming/Example.hs:29:3: error:
* No instance for (MonadResource Handler)
arising from a use of `runAWS'
* In a stmt of a 'do' block: runAWS env conduits
In the expression:
do env <- newEnv Discover
runAWS env conduits
In an equation for `server':
server
= do env <- newEnv Discover
runAWS env conduits
|
29 | runAWS env conduits
| ^^^^^^^^^^^^^^^^^^^
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我已经建立了一个存储库来重现:https://github.com/domenkozar/servant-streaming-amazonka
servant-streaming-server处理ResourceT的Stream (Of BS.ByteString) (ResourceT IO) () https://github.com/plow-technologies/servant-streaming/blob/master/servant-streaming-server/src/Servant/Streaming/Server/Internal.hs#L77-L79
但由于我正在使用Amazonka,我还需要确保Handler的MonadResource采用该括号.我不清楚如何做到这一点.
我的理解是使用enter/ hoistServer这将不起作用,因为资源将很快被清理(流式传输之前).
笔记:
$$了$$+-解决了
server :: Server API
server = do
env <- newEnv Discover
res <- runInternalState (runAWS env conduits) st
return (res >> liftIO (closeInternalState st))
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