Ste*_*ich 6 java jackson jackson-databind
考虑这个属性
@JsonProperty
private Map<String, Object> myMap;
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当一个包含的java.util.Date值被序列化时,它不会被Date再次反序列化,因为类型信息不存在于Map<String, Object>. 我怎样才能绕过这个问题?我阅读了有关此问题的答案,这将是一个解决方法,但无法区分包含日期的字符串和在地图中序列化为字符串的日期。我可以告诉 Jackson 为每个映射值包含类型信息,以便 Jackson 可以正确反序列化它们吗?
实现自定义反序列化器并将注释添加@JsonDeserialize(using = DateDeserializer.class)到您的字段。
看一下这个例子:
你的 Json-Bean:
public class Foo {
private String name;
@JsonProperty
@JsonDeserialize(using = DateDeserializer.class)
private Map<String, Object> dates;
[...] // getter, setter, equals, hashcode
}
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解串器:
public class DateDeserializer extends JsonDeserializer<Map<String, Object>> {
private TypeReference<HashMap<String, Object>> typeRef = new TypeReference<HashMap<String, Object>>() {};
@Override
public Map<String, Object> deserialize(JsonParser p, DeserializationContext ctxt, Map<String, Object> target) throws IOException, JsonProcessingException {
Map<String, Long> map = new ObjectMapper().readValue(p, typeRef);
for(Entry<String, Long> e : map.entrySet()){
Long value = e.getValue();
String key = e.getKey();
if(value instanceof Long){ // or if("date".equals(key)) ...
target.put(key, new Date(value));
} else {
target.put(key, value); // leave as is
}
}
return target;
}
@Override
public Map<String, Object> deserialize(JsonParser paramJsonParser, DeserializationContext ctxt) throws IOException, JsonProcessingException {
return this.deserialize(paramJsonParser, ctxt, new HashMap<>());
}
}
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简单测试:
public static void main(String[] args) throws Exception {
Foo foo1 = new Foo();
foo1.setName("foo");
foo1.setData(new HashMap<String, Object>(){{
put("date", new Date());
put("bool", true);
put("string", "yeah");
}});
ObjectMapper mapper = new ObjectMapper();
String jsonStr = mapper.writeValueAsString(foo1);
System.out.println(jsonStr);
Foo foo2 = mapper.readValue(jsonStr, Foo.class);
System.out.println(foo2.equals(foo1));
}
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