为pandas中的groupby计算nunique()

Sla*_*vka 6 python pandas pandas-groupby

我有一个带列的数据框:

  1. diff - 注册日期和付款日期之间的差异,以天为单位
  2. country - 用户国家
  3. user_id
  4. campaign_id -- 另一个分类列,我们将在 groupby 中使用它

我需要为每个具有<=n 的country+campaign_id组计算不同的用户diff数。例如,对于country'A'、campaign'abc' 和diff7,我需要从country'A'、campaign'abc' 和diff <= 7 中

我目前的解决方案(如下)工作时间太长

import pandas as pd
import numpy as np

## generate test dataframe
df = pd.DataFrame({
        'country':np.random.choice(['A', 'B', 'C', 'D'], 10000),
        'campaign': np.random.choice(['camp1', 'camp2', 'camp3', 'camp4', 'camp5', 'camp6'], 10000),
        'diff':np.random.choice(range(10), 10000),
        'user_id': np.random.choice(range(1000), 10000)
        })
## main
result_df = pd.DataFrame()
for diff in df['diff'].unique():
    tmp_df = df.loc[df['diff']<=diff,:]
    tmp_df = tmp_df.groupby(['country', 'campaign'], as_index=False).apply(lambda x: x.user_id.nunique()).reset_index()
    tmp_df['diff'] = diff
    tmp_df.columns=['country', 'campaign', 'unique_ppl', 'diff']
    result_df = pd.concat([result_df, tmp_df],ignore_index=True, axis=0)
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也许有更好的方法来做到这一点?

jez*_*ael 5

首先使用列表理解 with concatand assignfor join all together,然后groupbywith add nuniquecolumn diff,最后重命名列,并在必要时添加reindex自定义列顺序:

df1 = pd.concat([df.loc[df['diff']<=x].assign(diff=x) for x in  df['diff'].unique()])
df2 = (df1.groupby(['diff','country', 'campaign'], sort=False)['user_id']
          .nunique()
          .reset_index()
          .rename(columns={'user_id':'unique_ppl'})
          .reindex(columns=['country', 'campaign', 'unique_ppl', 'diff']))
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jpp*_*jpp 4

下面是一种替代方案,但@jezrael 的解决方案是最佳的。

性能基准测试

%timeit original(df)  # 149ms
%timeit jp(df)        # 81ms
%timeit jez(df)       # 47ms

def original(df):
    result_df = pd.DataFrame()
    for diff in df['diff'].unique():
        tmp_df = df.loc[df['diff']<=diff,:]
        tmp_df = tmp_df.groupby(['country', 'campaign'], as_index=False).apply(lambda x: x.user_id.nunique()).reset_index()
        tmp_df['diff'] = diff
        tmp_df.columns=['country', 'campaign', 'unique_ppl', 'diff']
        result_df = pd.concat([result_df, tmp_df],ignore_index=True, axis=0)

    return result_df

def jp(df):

    result_df = pd.DataFrame()
    lst = []
    lst_append = lst.append
    for diff in df['diff'].unique():
        tmp_df = df.loc[df['diff']<=diff,:]
        tmp_df = tmp_df.groupby(['country', 'campaign'], as_index=False).agg({'user_id': 'nunique'})
        tmp_df['diff'] = diff
        tmp_df.columns=['country', 'campaign', 'unique_ppl', 'diff']
        lst_append(tmp_df)

    result_df = result_df.append(pd.concat(lst, ignore_index=True, axis=0), ignore_index=True)

    return result_df

def jez(df):
    df1 = pd.concat([df.loc[df['diff']<=x].assign(diff=x) for x in  df['diff'].unique()])
    df2 = (df1.groupby(['diff','country', 'campaign'], sort=False)['user_id']
              .nunique()
              .reset_index()
              .rename(columns={'user_id':'unique_ppl'})
              .reindex(columns=['country', 'campaign', 'unique_ppl', 'diff']))
    return df2
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