Delphi XE中的SHA1散列

Leo*_*era 7 delphi cryptography sha1 delphi-xe

我正在实施XML数字签名.我从小步骤开始,所以现在我想解决SHA-1哈希的问题.

在SO中有很多关于此的问题:

  1. 数字签名密钥与锁箱
  2. Delphi的加密库
  3. 将此php数字签名转换为Delphi
  4. Delphi:是否有适用于Delphi-XE的LockBox版本
  5. Delphi 2010密码学库

......可能还有更多.但是,我正在使用Delphi XE.到目前为止,我已经试过的Lockbox 2(两个Songbeamer和Sourceforge的版本),锁箱3,DCPCrypto2和其他一些人(哈希值是一个易于使用的单位,使用Windows加密功能)

我准备了一个小型试验台,它给了我以下内容:

LockBox2

FAILED: 1 ('abc') 
       Got: '9f04f41a848514162050e3d68c1a7abb441dc2b5'
  Expected: 'a9993e364706816aba3e25717850c26c9cd0d89d'
FAILED: 2 ('abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq') 
       Got: '51d7d8769ac72c409c5b0e3f69c60adc9a039014'
  Expected: '84983e441c3bd26ebaae4aa1f95129e5e54670f1'
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LockBox3

FAILED: 1 ('abc') 
       Got: '9f04f41a848514162050e3d68c1a7abb441dc2b5'
  Expected: 'a9993e364706816aba3e25717850c26c9cd0d89d'
FAILED: 2 ('abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq') 
       Got: '51d7d8769ac72c409c5b0e3f69c60adc9a039014'
  Expected: '84983e441c3bd26ebaae4aa1f95129e5e54670f1'
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DCPCrypto2

FAILED: 1 ('abc') 
       Got: '9f04f41a848514162050e3d68c1a7abb441dc2b5'
  Expected: 'a9993e364706816aba3e25717850c26c9cd0d89d'
FAILED: 2 ('abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq') 
       Got: '51d7d8769ac72c409c5b0e3f69c60adc9a039014'
  Expected: '84983e441c3bd26ebaae4aa1f95129e5e54670f1'
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哈希

Test 1 passes
Test 2 passes
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您是否已成功在Delphi XE下编译提到的库并使它们具有适当的值?我对DCPCrypt2 SelfTest程序特别感兴趣.

编辑:我已经用固定的源代码添加了这个答案.谢谢大家的帮助,非常感谢.

RRU*_*RUZ 26

莱昂纳多,我认为UNICODE当你使用函数散列你的问题时,你的问题是string传递一个字节的数组(缓冲区).所以当您abc在Delphi XE中传递字符串时,您正在散列这样的缓冲区61 00 62 00 63 00(十六进制表示)

检查此示例应用程序,该应用程序使用Jwscl library(JEDI Windows安全代码库)中的Windows加密函数

program Jwscl_TestHash;

{$APPTYPE CONSOLE}

uses
  JwsclTypes,
  JwsclCryptProvider,
  Classes,
  SysUtils;

function GetHashString(Algorithm: TJwHashAlgorithm; Buffer : Pointer;Size:Integer) : AnsiString;
var
  Hash: TJwHash;
  HashSize: Cardinal;
  HashData: Pointer;
  i       : Integer;
begin
  Hash := TJwHash.Create(Algorithm);
  try
    Hash.HashData(Buffer,Size);
    HashData := Hash.RetrieveHash(HashSize);
    try
        SetLength(Result,HashSize*2);
        BinToHex(PAnsiChar(HashData),PAnsiChar(Result),HashSize);
    finally
      TJwHash.FreeBuffer(HashData);
    end;
  finally
    Hash.Free;
  end;
end;


function GetHashSHA(FBuffer : AnsiString): AnsiString;
begin
   Result:=GetHashString(haSHA,@FBuffer[1],Length(FBuffer));
end;

function GetHashSHA_Unicode(FBuffer : String): String;
begin
   Result:=GetHashString(haSHA,@FBuffer[1],Length(FBuffer)*SizeOf(Char));
end;

begin
 try
     Writeln(GetHashSHA('abc'));
     Writeln(GetHashSHA('abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq'));
     Writeln(GetHashSHA_Unicode('abc'));
     Writeln(GetHashSHA_Unicode('abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq'));
     Readln;
 except
    on E:Exception do
    begin
        Writeln(E.Classname, ':', E.Message);
        Readln;
    end;
 end;

end.
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这回归

abc AnsiString类型

A9993E364706816ABA3E25717850C26C9CD0D89D

abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq AnsiString类型

84983E441C3BD26EBAAE4AA1F95129E5E54670F1 for

abc 统一

9F04F41A848514162050E3D68C1A7ABB441DC2B5

abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq 统一

51D7D8769AC72C409C5B0E3F69C60ADC9A039014


Bar*_*lly 19

我的Cygwin命令提示符告诉我确实是Unicode让你感到困惑:

~$ printf 'a\0b\0c\0' | sha1sum
9f04f41a848514162050e3d68c1a7abb441dc2b5 *-
~$ printf 'abc' | sha1sum
a9993e364706816aba3e25717850c26c9cd0d89d *-
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Tho*_*ler 6

期望值是否可以用于ANSI字符串,而您获得的哈希值是否为unicode字符串?