Ruby zip 3 数组分两步

use*_*535 2 ruby ruby-on-rails ruby-on-rails-4

我有以下数组:

product_ids = ['id', 'id', 'id'...'id']
product_prices = ['price', 'price', 'price'...'price']
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第一步,我执行以下操作

list_1 = product_ids.zip(product_prices)
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在这一点上,我有一个带有表单的列表

list_1 -> [['id', 'price'],['id','price']...]
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经过一些计算,我得到了另一个数组

warehouses_stocks = [['stock_1', 'stock_1'..],['stock_2','stock_2'...]]
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我如何合并这两个(list_1 和仓库_stocks)以获取另一个具有以下形式的数组

[['id','price', 'stock_1', 'stock_2'],['id','price', 'stock_1', 'stock_2'],...]
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Sag*_*dya 5

product_ids = ['id_1', 'id_2']
product_prices = ['price_1', 'price_2']
warehouses_stocks = [['stock_1', 'stock_1'],['stock_2','stock_2']]
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zip 可以采用多个参数:

product_ids.zip(product_prices, *warehouses_stocks)
#=> [["id_1", "price_1", "stock_1", "stock_2"],
#    ["id_2", "price_2", "stock_1", "stock_2"]]
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