错误：已将握手入队后无法入队握手

Question

我正在从不同来源获取新闻提要并添加到数据库中，但出现以下异常

错误：已将握手入队后无法入队握手。在 Protocol._validateEnqueue (/home/vikas/node_modules/mysql/lib/protocol/Protocol.js:210:16) 在 Protocol._enqueue (/home/vikas/node_modules/mysql/lib/protocol/Protocol.js:139: 13) 在 Protocol.handshake (/home/vikas/node_modules/mysql/lib/protocol/Protocol.js:52:23) 在 Connection.connect (/home/vikas/node_modules/mysql/lib/Connection.js:130: 18) 在 storeNewsFeedsInDB (/home/vikas/NodeJS Practice/fetchNews.js:42:7) at newsapi.v2.everything.then.response (/home/vikas/NodeJS Practice/fetchNews.js:33:9) at tryCatcher (/home/vikas/node_modules/bluebird/js/release/util.js:16:23) at Promise._settlePromiseFromHandler (/home/vikas/node_modules/bluebird/js/release/promise.js:512:31) at Promise .

下面是我的代码

const NewsAPI = require('newsapi');
const newsapi = new NewsAPI('*****************************');

var mysql = require('mysql');
var con = mysql.createConnection({
  host: "****",
  user: "****",
  password: "****",
  database: "****"
});

var channels = ['bbc-news', 'the-verge', 'reuters', 'cnbc', 'bloomberg', 'economist', 'nytimes'];
var topics = ['technology', 'business', 'finance', 'tech', 'economics', 'company'];

for (var i = 0; i < channels.length; i++) {
  for (var j = 0; j < topics.length; j++) {
    newsapi.v2.everything({
      q: topics[j],
      // q: 'technology',
      sources: channels[i],
      // sources: 'bloomberg',
      // domains: 'bbc.co.uk, techcrunch.com',
      from: '2018-03-14',
      to: '2018-03-14',
      language: 'en',
      sortBy: 'relevancy',
      pageSize:100,
      page: 1
    }).then(response => {
      // console.log(response);
      for (var i = 0; i < response.articles.length; i++) {
        // console.log(response.articles[i].title);
        storeNewsFeedsInDB(response.articles[i].title, 
                            response.articles[i].description, 
                              response.articles[i].url);
      }
    });
  }
}

function storeNewsFeedsInDB(title, description, url) {
  con.connect(function(err) {
    if (err) throw err;
    console.log("Connected!");

    //Insert a record in the "newsfeeds" table:
    var sql = "INSERT IGNORE INTO newsfeeds (`title`, `description`, `url`) VALUES ('" 
                + title.replace(/'/g, "\\'") + "', '" + description.replace(/'/g, "\\'") + "', '" + url + "')";
                console.log(sql);
    con.query(sql, function (err, result) {
      if (err) throw err;
      console.log("1 record inserted");
    });
  });
}

Nodejs & Mysql 新手，请帮帮我。

Answer 1

您storeNewsFeedsInDB从（嵌套）循环内部调用，每次访问它时都调用con.connect，这就是为什么您会收到“排队握手”错误的原因。一看的一个mysqlNPM软件包测试可以揭示，由于误差只要连续两次抛出con.connect调用制成。

您应该只con.connect从代码中删除该调用，因为任何query调用都隐式地建立了连接，正如文档所说。