如何从流本身中取消无限流?

ope*_*eek 6 future stream rust rust-tokio

我试图interval_timer在清空队列后取消间隔 ( ),但不确定什么是正确的策略。

let mut some_vars = vec![1, 2, 3, 4, 5, 6, 7, 8];
let interval_timer = tokio_timer::Timer::default();

let timer = interval_timer
    .interval(Duration::from_millis(1000))
    .map_err(|_| {
        println!("Errored out");
    });

let s = timer.for_each(move |_| {
    println!("Woke up");
    let item = some_vars.pop().unwrap();

    let f = futures::future::ok(item).map(|x| {
        println!("{:?}", x);
    });
    tokio::spawn(f)
});

tokio::run(s);
Run Code Online (Sandbox Code Playgroud)

drop按照 gitter 中的建议进行了尝试,但最终出现错误:

let mut some_vars = vec![1, 2, 3, 4, 5, 6, 7, 8];
let mut interval_timer = tokio_timer::Timer::default();

let timer = interval_timer
    .interval(Duration::from_millis(1000))
    .map_err(|_| {
        println!("Errored out");
    });

let s = timer.for_each(move |_| {
    println!("Woke up");
    if some_vars.len() == 1 {
        drop(interval_timer);
    }

    let item = some_vars.pop().unwrap();

    let f = futures::future::ok(item).map(|x| {
        println!("{:?}", x);
    });
    tokio::spawn(f)
});

tokio::run(s);
Run Code Online (Sandbox Code Playgroud)

错误:

let mut some_vars = vec![1, 2, 3, 4, 5, 6, 7, 8];
let interval_timer = tokio_timer::Timer::default();

let timer = interval_timer
    .interval(Duration::from_millis(1000))
    .map_err(|_| {
        println!("Errored out");
    });

let s = timer.for_each(move |_| {
    println!("Woke up");
    let item = some_vars.pop().unwrap();

    let f = futures::future::ok(item).map(|x| {
        println!("{:?}", x);
    });
    tokio::spawn(f)
});

tokio::run(s);
Run Code Online (Sandbox Code Playgroud)

She*_*ter 4

对于想要从流外部取消流的情况,请参阅stream-cancel


对于您的具体情况,最简单的方法是将您的集合转换为流并将其与间隔计时器一起压缩。这样,当集合为空时,结果流自然停止:

use futures::{future, stream, Stream}; // 0.1.29
use std::time::Duration;
use tokio; // 0.1.22
use tokio_timer::Interval; // 0.2.11

fn main() {
    tokio::run({
        let some_vars = vec![1, 2, 3, 4, 5, 6, 7, 8];

        let timer =
            Interval::new_interval(Duration::from_millis(100)).map_err(|e| panic!("Error: {}", e));

        let some_vars = stream::iter_ok(some_vars.into_iter().rev());
        let combined = timer.zip(some_vars);

        combined.for_each(move |(_, item)| {
            eprintln!("Woke up");

            tokio::spawn(future::lazy(move || {
                println!("{:?}", item);
                Ok(())
            }));

            Ok(())
        })
    });
}
Run Code Online (Sandbox Code Playgroud)

否则,您可以通过使用and_then从集合中删除值并控制流是否应继续来停止流:

use futures::{future, Stream}; // 0.1.29
use std::time::Duration;
use tokio; // 0.1.22
use tokio_timer::Interval; // 0.2.11

fn main() {
    tokio::run({
        let mut some_vars = vec![1, 2, 3, 4, 5, 6, 7, 8];

        let timer =
            Interval::new_interval(Duration::from_millis(100)).map_err(|e| panic!("Error: {}", e));

        let limited = timer.and_then(move |_| {
            if some_vars.len() <= 4 {
                Err(())
            } else {
                some_vars.pop().ok_or(())
            }
        });

        limited.for_each(move |item| {
            eprintln!("Woke up");

            tokio::spawn(future::lazy(move || {
                println!("{:?}", item);
                Ok(())
            }));

            Ok(())
        })
    });
}
Run Code Online (Sandbox Code Playgroud)