Sla*_*ion 0 python replace list find multidimensional-array
类似于这个问题:查找和替换列表(python)中的元素, 但使用多维数组。例如,我想用 0 替换所有 N:
list =
[['N', 0.21],
[-1, 6.6],
['N', 34.68]]
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我想把它改成:
list =
[[0, 0.21],
[-1, 6.6],
[0, 34.68]]
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您可以使用嵌套列表理解:
l = [['N', 0.21], [-1, 6.6], ['N', 34.68]]
new_l = [[0 if b == 'N' else b for b in i] for i in l]
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输出:
[[0, 0.21], [-1, 6.6], [0, 34.68]]
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