ham*_*yad 2 selenium xpath href python-3.x webscarab
如果我的代码是这样的话:
x=driver.find_element_by_xpath("""//*[@id="react-root"]/section/main/article/div[1]/div/div/div[1]/div[2]/a""")
x.click()
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但是,发生此错误:
selenium.common.exceptions.ElementNotInteractableException: Message: Element <a href="/p/BgEcF34Fqf6/?tagged=fast"> could not be scrolled into view
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请问你能帮帮我吗?
试用JavaScript单击:
from selenium.webdriver.remote.webelement import WebElement
def javascript_click(self, locator):
element = None
if isinstance(locator, str):
element = self.find_element(locator)
elif isinstance(locator, WebElement):
element = locator
if element is not None:
self._driver.execute_script("arguments[0].click();", element)
else:
raise Exception("Could not click on locator " + element)
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