如何从Core 2 RazorPage ViewModel处理程序返回PartialView

Question

在Asp.Net MVC中,您可以通过执行以下操作轻松返回部分视图:

return PartialView("ModelName", Model);

这是如何在RazorPage ViewModel处理程序上完成的？

Answer 1

我想通了.它并不像MVC那样直截了当.您必须创建一个空ViewDataDictionary(),然后将其Model属性设置为partial的填充模型.

查看模型/处理程序

public async Task<IActionResult> OnGetAsyncUpdateSearchResults(DateTime startDate, DateTime endDate, string selectedTypes)
{
    int[] types = selectedTypes.Split(",").Select(x => int.Parse(x)).ToArray();

    var inventory = await _itemService.GetFiltered(types, null, null, null, null, null, null, startDate, endDate.ToUniversalTime(), null, null, null, null, null, null, null);

    if (inventory != null)
    {
        SearchResultsGridPartialModel = new SearchResultsGridPartialModel();
        SearchResultsGridPartialModel.TotalCount = inventory.TotalCount;
        SearchResultsGridPartialModel.TotalPages = inventory.TotalPages;
        SearchResultsGridPartialModel.PageNumber = inventory.PageNumber;
        SearchResultsGridPartialModel.Items = inventory.Items;
    }

    var myViewData = new ViewDataDictionary(new Microsoft.AspNetCore.Mvc.ModelBinding.EmptyModelMetadataProvider(), new Microsoft.AspNetCore.Mvc.ModelBinding.ModelStateDictionary()) { { "SearchResultsGridPartialModel", SearchResultsGridPartialModel } };
    myViewData.Model = SearchResultsGridPartialModel;

    PartialViewResult result = new PartialViewResult()
    {
        ViewName = "SearchResultsGridPartial",
        ViewData = myViewData,
    };

    return result;
}

我现在可以通过ajax GET调用这个处理程序并让它返回部分的HTML.然后我可以div按预期设置部分刷新和部分刷新.

这是我正在制作的AJAX调用:

var jsonData = { "startDate": startDate, "endDate": endDate, "selectedTypes": selectedTypesAsString };

$.ajax({
    type: 'GET',
    url: "searchresults/?handler=AsyncUpdateSearchResults",
    beforeSend: function (xhr) {
        xhr.setRequestHeader("XSRF-TOKEN", $('input:hidden[name="__RequestVerificationToken"]').val());
    },
    contentType: 'application/json; charset=utf-8"',
    data: jsonData,
    success: function (result) {
        $("#searchResultsGrid").html(result);
    },
    error: function (error) {
        console.log(error);
    }
});

Answer 2

Thanks alot to TechFisher for figuring it out, here is a bit cleaner example.

public IActionResult OnGetTestPartial()
{
    return new PartialViewResult()
    {
        ViewName = "Test",
        ViewData = new ViewDataDictionary(new EmptyModelMetadataProvider(), new ModelStateDictionary())
        {
            Model = new TestPartialData { Data = "inputhere" },
        }
    };
}

Partial view in a file name "Test.cshtml" in the same folder as the above class.

@using YourNamespace
@model TestPartialData

<div>Hello, model value: @Model.Data</div>

Load it async with jquery

$("#someHtmlElementId").load("Your/Path/TestPartial");