为什么Rails 3中的AJAX如此难？或者,我做错了什么？

Question

没有一个教程我似乎做了我想要做的事情.很简单,我希望用户能够向控制器提交POST请求("喜欢"视频)并让控制器使用JSON对象进行响应.任何帮助,将不胜感激.

谢谢

编辑因为SO正在弄乱格式化,这里也是我的代码的要点:https: //gist.github.com/813503

这是我的控制器:

class LikesController < ApplicationController

  before_filter :get_ids

  respond_to :json, :js

  def videolink
    results = {}

    # check to see if the user has liked this videolink before
    if current_user
      liked = Like.video?(current_user, @vid_id)

      results["status"] = "OK"      
      results["liked"] = liked
    else
      results["status"] = "Error"
      results["message"] = "User not logged in"
    end

    respond_with( results.to_json ) 
  end


  def update
    results = {}

    if current_user
      results["status"] = "OK"  
    else
      results["status"] = "Error"
      results["message"] = "User not logged in"
    end

    respond_with( results.to_json )
  end


  private

  def get_ids
    @vid_id = params[:videolink_id]
  end

end

这是我的JS文件:

$("#likeVideo").click(function() {
    $.ajax({
        contentType: "application/json",
        data: { game_id: game_id,   videolink_id: current_video["videolink"]["id"] },
        dataType: "json",
        type: "POST",
        url: "/likes/" + game_id,
        success: function(data) {
            console.log("Success", data);
        }
    });     

    return false;
});

我的路线:

  resources :likes do
    collection do
      get "videolink"
    end

    member do
      post :update
    end
  end

这是我得到的错误:

NoMethodError in LikesController#update

undefined method `{"status":"OK"}_url' for #<LikesController:0x0000010178be58>

NoMethodError in LikesController#update

undefined method `{"status":"OK"}_url' for #<LikesController:0x0000010178be58>

Answer 1

如果要发回自定义JSON,而不是respond_with(results.to_json)...只是渲染文本

render :text=>results.to_json

responds_with是一种让您轻松发回物品及其位置(url)的方法.这就是为什么你的错误告诉你"_url"无效的原因.

有关responds_with的更多信息,请参阅http://ryandaigle.com/articles/2009/8/10/what-s-new-in-edge-rails-default-restful-rendering

如果请求了另一种格式,(即:xml或:json)

• 如果是GET请求,则在资源上调用:to_format方法并将其发回
• 如果资源有验证错误,请使用:unprocessable_entity状态代码以请求的格式发回错误
• 如果是POST请求,则在资源上调用:to_format方法,然后将其发送回:created status和新创建的资源的:location
• 否则,发回:ok响应,没有身体