PHP AJAX和mySQL没有返回数据?

Bar*_*der 0 php mysql ajax

我有以下PHP块:

$word = mysql_real_escape_string(trim($_GET['word']));
    $firstletter = substr('$word', 0, 1);

    $query = "SELECT * FROM `dictionary` WHERE word LIKE '%$firstletter'";
    $result = mysql_query($query) or die(mysql_error().": ".$query);
    $row = mysql_fetch_assoc($result);
    // send back the word to ajax request
    $i = 0;
    $fullLoad = '';
    while ($i < mysql_numrows($result)) {
        $fullLoad = $fullload . '|' . $row['word'];
        $i++;
    }
    echo $fullLoad;
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现在,我的AJAX电话:

$.ajax({
                type: "GET",
                url: "word-list.php",
                data: "word="+ theword,
                success: function(data){ //data retrieved
                    console.log(data);
                            }
    });
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现在,让我们假设缺少的单词变量是apple- 所以$word = 'apple';

但是当console.log()输出时 - 我得到的只有零,没有,nada,zip,blahblah

> :(

RSK*_*RSK 6

试试这个

 $firstletter = substr($word, 0, 1);
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