Jia*_* Li 7 java generics bounded-wildcard
对于Comparator类中的比较源代码
public static <T, U extends Comparable<? super U>> Comparator<T> comparing(
Function<? super T, ? extends U> keyExtractor)
{
Objects.requireNonNull(keyExtractor);
return (Comparator<T> & Serializable) (c1, c2) -> keyExtractor.apply(c1).compareTo(keyExtractor.apply(c2));
}
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我明白之间的差别super和extends.我不明白的是,为什么这种方法有它们.有人能举例说明参数看起来像什么时无法实现的Function<T, U> keyExtractor?
例如 :
Comparator<Employee> employeeNameComparator = Comparator.comparing(Employee::getName);
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也可以使用以下函数定义进行编译
public static <T, U extends Comparable<? super U>> Comparator<T> comparing(
Function<T, U> keyExtractor)
{
Objects.requireNonNull(keyExtractor);
return (Comparator<T> & Serializable) (c1, c2) -> keyExtractor.apply(c1).compareTo(keyExtractor.apply(c2));
}
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这是一个简单的例子:按重量比较汽车.我将首先以文本形式描述问题,然后展示如果省略? extends或? super忽略它可能出错的每种可能方式.我还展示了在每种情况下都可用的丑陋的部分解决方法.如果您更喜欢代码而不是散文,请直接跳到第二部分,它应该是不言自明的.
首先是逆变? super T.
假设你有两个类Car,PhysicalObject那样Car extends PhysicalObject.现在假设你有一个Weight扩展的功能Function<PhysicalObject, Double>.
如果声明是Function<T,U>,那么你不能重复使用该功能Weight extends Function<PhysicalObject, Double>来比较两辆车,因为Function<PhysicalObject, Double>不符合Function<Car, Double>.但你显然希望能够按重量比较汽车.因此,逆变? super T是有道理的,因此Function<PhysicalObject, Double>符合Function<? super Car, Double>.
现在的协变? extends U声明.
假设你有两个类Real和PositiveReal这样PositiveReal extends Real,而且认为Real是Comparable.
假设您Weight上一个示例中的函数实际上具有稍微更精确的类型Weight extends Function<PhysicalObject, PositiveReal>.如果申报keyExtractor人Function<? super T, U>的而不是Function<? super T, ? extends U>,您将无法充分利用的事实,PositiveReal也是一个Real,因此有两个PositiveReals不能互相比较,虽然它们实现Comparable<Real>,没有不必要的限制Comparable<PositiveReal>.
总结:与声明Function<? super T, ? extends U>,则Weight extends Function<PhysicalObject, PositiveReal>可以替换为一个Function<? super Car, ? extends Real>比较Car使用S Comparable<Real>.
我希望这个简单的例子澄清了为什么这样的声明是有用的.
? extends或被? super忽略的后果这里是所有的东西都不可能去错的,如果我们忽略任何一个系统的枚举编译例子? super或? extends.此外,还显示了两个(丑陋的)部分解决方案.
import java.util.function.Function;
import java.util.Comparator;
class HypotheticComparators {
public static <A, B> Comparator<A> badCompare1(Function<A, B> f, Comparator<B> cb) {
return (A a1, A a2) -> cb.compare(f.apply(a1), f.apply(a2));
}
public static <A, B> Comparator<A> badCompare2(Function<? super A, B> f, Comparator<B> cb) {
return (A a1, A a2) -> cb.compare(f.apply(a1), f.apply(a2));
}
public static <A, B> Comparator<A> badCompare3(Function<A, ? extends B> f, Comparator<B> cb) {
return (A a1, A a2) -> cb.compare(f.apply(a1), f.apply(a2));
}
public static <A, B> Comparator<A> goodCompare(Function<? super A, ? extends B> f, Comparator<B> cb) {
return (A a1, A a2) -> cb.compare(f.apply(a1), f.apply(a2));
}
public static void main(String[] args) {
class PhysicalObject { double weight; }
class Car extends PhysicalObject {}
class Real {
private final double value;
Real(double r) {
this.value = r;
}
double getValue() {
return value;
}
}
class PositiveReal extends Real {
PositiveReal(double r) {
super(r);
assert(r > 0.0);
}
}
Comparator<Real> realComparator = (Real r1, Real r2) -> {
double v1 = r1.getValue();
double v2 = r2.getValue();
return v1 < v2 ? 1 : v1 > v2 ? -1 : 0;
};
Function<PhysicalObject, PositiveReal> weight = p -> new PositiveReal(p.weight);
// bad "weight"-function that cannot guarantee that the outputs
// are positive
Function<PhysicalObject, Real> surrealWeight = p -> new Real(p.weight);
// bad weight function that works only on cars
// Note: the implementation contains nothing car-specific,
// it would be the same for every other physical object!
// That means: code duplication!
Function<Car, PositiveReal> carWeight = p -> new PositiveReal(p.weight);
// Example 1
// badCompare1(weight, realComparator); // doesn't compile
//
// type error:
// required: Function<A,B>,Comparator<B>
// found: Function<PhysicalObject,PositiveReal>,Comparator<Real>
// Example 2.1
// Comparator<Car> c2 = badCompare2(weight, realComparator); // doesn't compile
//
// type error:
// required: Function<? super A,B>,Comparator<B>
// found: Function<PhysicalObject,PositiveReal>,Comparator<Real>
// Example 2.2
// This compiles, but for this to work, we had to loosen the output
// type of `weight` to a non-necessarily-positive real number
Comparator<Car> c2_2 = badCompare2(surrealWeight, realComparator);
// Example 3.1
// This doesn't compile, because `Car` is not *exactly* a `PhysicalObject`:
// Comparator<Car> c3_1 = badCompare3(weight, realComparator);
//
// incompatible types: inferred type does not conform to equality constraint(s)
// inferred: Car
// equality constraints(s): Car,PhysicalObject
// Example 3.2
// This works, but with a bad code-duplicated `carWeight` instead of `weight`
Comparator<Car> c3_2 = badCompare3(carWeight, realComparator);
// Example 4
// That's how it's supposed to work: compare cars by their weights. Done!
Comparator<Car> goodComparator = goodCompare(weight, realComparator);
}
}
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相关链接
比方说,例如,我们想通过他们使用的飞机来比较商业航班。因此,我们需要一个接收航班并返回飞机的方法:
Plane func (CommercialFlight)
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那当然是一个Function<CommercialFlight, Plane>。
现在,重要的是该函数返回一个Plane. 返回什么样的飞机并不重要。所以像这样的方法也应该有效:
CivilianPlane func (CommercialFlight)
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现在从技术上讲,这是 a Function<CommercialFlight, CivilianPlane>,与Function<CommercialFlight, Plane>. So without theextends 不同,不允许使用此功能。
同样,另一个重要的事情是可以接受 aCommercialFlight作为参数。所以像这样的方法也应该有效:
Plane func (Flight)
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从技术上讲,这是一个Function<Flight, Plane>,它也不同于Function<CommercialFlight, Plane>。所以没有super,这个功能也不会被允许。