Rails 3将资源路由问题嵌套为form_for

Fab*_*ani 14 routes form-for ruby-on-rails-3

我在routes.rb中嵌套了这样的资源 - (我的rake:routes gist)

namespace(:admin) do 
  resources :restaurants do
    resources :menus
    resources :menu_items
  end
end
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在控制器中:

def new 
  @restaurant = Restaurant.find(params[:restaurant_id])
  @menu_item =  @restaurant.menu_items.build
end
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试图通过网址创建一个新的MenuItem(action #new):http://127.0.0.1:03001/admin/restaurant/lamen_items/new 我收到错误:

NoMethodError in Admin/menu_items#new

Showing /home/fps/workspace3/peded/app/views/admin/menu_items/_form.html.erb where line #1 raised:

undefined method `admin_menu_items_path' for #<#<Class:0xb6582d78>:0xb6581f2c>
Extracted source (around line #1):

1: <%= form_for @menu_item do |f| %>
...
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如何使这个表格有效?它是由一个漂亮的脚手架创建的

UPDATE

我也在_form中试过这个:

<%= form_for [:restaurant, @menu_item] do |f| %>
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但以类似的错误结束:

Showing /home/fps/workspace3/peded/app/views/admin/menu_items/_form.html.erb where line #1 raised:

undefined method `restaurant_admin_menu_items_path' for #<#<Class:0xb68162b0>:0xb6813dd0>
Extracted source (around line #1):

1: <%= form_for [:restaurant, @menu_item] do |f| %
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我应该提交错误吗?

Ult*_*ion 12

form_for([@restaurant, @menu_item])


Sco*_*ott 11

我认为问题在于形式.这对我有用:

<%= form_for(@menu_items, :url => restaurant_menu_items_path(@menu_items.restaurant)) do |f| %>
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  • 使用这种方法,我得到错误:没有路由匹配{:action =>"show",:controller =>"menu_items"} (3认同)

Ben*_*ler 8

我有同样的问题.我找到的唯一解决方案是将URL传递给form_for.

<% url = (action_name == "new" ? {:action=>"create", :controller=>"admin/menu_item"} : {:action=>"update", :controller=>"admin/menu_item"})%>

<%= form_for [@restaurant ,@menu_item], :url=>url do |f| %>
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另外一个注意事项,你不会得到params[:menu_item] back,相反你会看到params[:admin_menu_item].

希望能帮到你!