Dav*_*eri 14 c gcc clang compound-literals designated-initializer
用gcc -std=c99 -Wextra这段代码编译:
#include <stdio.h>
struct T {
int a;
int *b;
int c;
};
int main(void)
{
struct T t = {.b = ((int []){1, 1})};
printf("%d\n", t.b[1]);
return 0;
}
Run Code Online (Sandbox Code Playgroud)
给我一个警告:
demo.c:11:12: warning: missing initializer for field ‘c’ of ‘struct T’ [-Wmissing-field-initializers]
struct T t = {.b = ((int []){1, 1})};
^
demo.c:6:9: note: ‘c’ declared here
int c;
^
Run Code Online (Sandbox Code Playgroud)
但是指定的初始值设定项应该初始化为其余成员的零,即使它们被省略.
为什么警告?(clang编译同一段代码而不发出警告)
gcc version 6.3.0 20170516 (Debian 6.3.0-18)
clang version 3.8.1-24 (tags/RELEASE_381/final)
Run Code Online (Sandbox Code Playgroud)
小智 2
它看起来像一个 gcc“一致性错误”,这里是相关的代码片段gcc/c/c-typeck.c
7436 /* Warn when some struct elements are implicitly initialized to zero. */
7437 if (warn_missing_field_initializers
7438 && constructor_type
7439 && TREE_CODE (constructor_type) == RECORD_TYPE
7440 && constructor_unfilled_fields)
7441 {
7442 bool constructor_zeroinit =
7443 (vec_safe_length (constructor_elements) == 1
7444 && integer_zerop ((*constructor_elements)[0].value));
7445
7446 /* Do not warn for flexible array members or zero-length arrays. */
7447 while (constructor_unfilled_fields
7448 && (!DECL_SIZE (constructor_unfilled_fields)
7449 || integer_zerop (DECL_SIZE (constructor_unfilled_fields))))
7450 constructor_unfilled_fields = DECL_CHAIN (constructor_unfilled_fields);
7451
7452 if (constructor_unfilled_fields
7453 /* Do not warn if this level of the initializer uses member
7454 designators; it is likely to be deliberate. */
7455 && !constructor_designated
7456 /* Do not warn about initializing with ` = {0}'. */
7457 && !constructor_zeroinit)
7458 {
7459 if (warning_at (input_location, OPT_Wmissing_field_initializers,
7460 "missing initializer for field %qD of %qT",
7461 constructor_unfilled_fields,
7462 constructor_type))
7463 inform (DECL_SOURCE_LOCATION (constructor_unfilled_fields),
7464 "%qD declared here", constructor_unfilled_fields);
7465 }
7466 }
Run Code Online (Sandbox Code Playgroud)
代码的目的似乎是警告任何属性构造函数是否有未填充的字段。事实上,您没有收到有关元素“a”的警告,这可能是这里的“一致性错误”。
如果-Wextra打算打开缺少初始化器警告,那么它已经打开了。问题是,“缺少初始化器警告”是否应该排除省略的属性?看来 gcc 和 clang 对此意见不一 - 他们这样做可能没问题吗?
这可能不是您正在寻找的答案..但希望它有助于您了解情况。:)。GCC 团队存在一致性错误,但他们的代码意图似乎在这些情况下发出警告,而从经验来看,clang 不会。
| 归档时间: |
|
| 查看次数: |
397 次 |
| 最近记录: |