ZeroMQ操作抛出EXC:[当前状态下无法完成操作]

Question

我正在尝试创建一个能够发送数据然后接收它们的类.

现在,它只适用于第一次发送/接收,而另一次尝试.send()它将在下面抛出错误.

>Traceback (most recent call last):
  File "main.py", line 31, in <module>
    zq.send(arr)
  File "D:\ITIM\video2\MQCompare\cZMQ.py", line 17, in send
    self.socketC.send(data)
  File "zmq/backend/cython/socket.pyx", line 636, in zmq.backend.cython.socket.S
ocket.send (zmq\backend\cython\socket.c:7305)
  File "zmq/backend/cython/socket.pyx", line 683, in zmq.backend.cython.socket.S
ocket.send (zmq\backend\cython\socket.c:7048)
  File "zmq/backend/cython/socket.pyx", line 206, in zmq.backend.cython.socket._
send_copy (zmq\backend\cython\socket.c:3032)
  File "zmq/backend/cython/socket.pyx", line 201, in zmq.backend.cython.socket._
send_copy (zmq\backend\cython\socket.c:2920)
  File "zmq/backend/cython/checkrc.pxd", line 25, in zmq.backend.cython.checkrc.
_check_rc (zmq\backend\cython\socket.c:10014)
    raise ZMQError(errno)
zmq.error.ZMQError: Operation cannot be accomplished in current state`

我正在使用的代码如下所示:

import zmq

class ZeroMQ:

def __init__(self):
    self.context = zmq.Context()
    self.socketS = self.context.socket(zmq.REP)
    self.socketS.bind("tcp://*:5555")
    self.socketC = self.context.socket(zmq.REQ)
    self.socketC.connect("tcp://localhost:5555")

def __exit__(self, exc_type, exc_value, traceback):
    self.socketC.close()
    self.socketS.close()

def send(self, data):
    self.socketC.send(data)

def recv(self):    
    self.socketS.recv()

我连接正确吗？

为什么函数发送错误？

我将不胜感激任何帮助.谢谢.

Answer 1

仅仅因为socketC作为REQ原型的实例,不能发送另一条消息(如.send()上面的类方法的实现中编码的那样),而不事先调用socketC.recv()instance-method.

两者REQ和REP原型都有很好的记录,必须服从两步舞蹈.send()-.recv()-.send()-.recv()-.....recv()-.send()-.recv()-...使用他们的本机实例方法.

这就是ZeroMQ REQ / REP 插座的设计和记录方式.