如何在 JavaScript 中将 IF 转换为 SWITCH 语句?

New*_*bie 5 javascript if-statement switch-statement

我接到了一项任务,我自己几乎已经解决了,但需要进行一些小的更正,我需要有人帮助我指出在哪里对我的代码进行一些外观更改:

这是任务:

将多条件 if 语句示例代码转换为 switch 示例代码。

var myAge = parseInt(prompt("Enter your age", 30), 10);

if (myAge >= 0 && myAge <= 10) {
  document.write("myAge is between 0 and 10<br />");
}

if (!(myAge >= 0 && myAge <= 10)) {
  document.write("myAge is NOT between 0 and 10<br />");
}

if (myAge >= 80 || myAge <= 10) {
  document.write("myAge is 80 or above OR 10 or below<br />");
}

if ((myAge >= 30 && myAge <= 39) || (myAge >= 80 && myAge <= 89)) {
  document.write("myAge is between 30 and 39 or myAge is " + "between 80 and 89");

}
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<DOCTYPE html>

  <html lang="en">
  <head>
    <title>SOME CODE</title>
  </head>

  <body>
  </body>
  </html>
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所以 30 岁以下的默认结果是:

myAge 不在 0 到 10 之间 myAge 在 30 到 39 之间或 myAge 是

80 到 89 之间

这是我到目前为止所做的:

var myAge = parseInt(prompt("Enter your age", 30), 10); // Get the user's response, converted to a number
switch (true) { // Switch statement if the condition is True
  case myAge >= 0 && myAge <= 10: // Check the inputs value in range 0 - 10                     
    document.write("myAge is between 0 and 10<br/>");
    break;
  case (!(myAge >= 0 && myAge <= 10)): // Check the inputs value if it's not a in range between 0 - 10 ( !(myAge >= 0 && myAge <= 10) )
    document.write("myAge is NOT between 0 and 10<br/>");
    break;
  case myAge >= 80 || myAge <= 10: // Check the inputs value if it's greater/equal to 80 OR less/equal to 10
    document.write("myAge is 80 or above OR 10 or below<br/>");
    break;
  default:
    document.write("myAge is between 30 and 39 or myAge is " + "between 80 and 89"); // Check the inputs value in range 30 - 39 And 80 - 89 

}
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<DOCTYPE html>

  <html lang="en">
  <head>
    <title>Chapter 3, Example 2</title>
  </head>
  <body>
  </body>
  </html>
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而且,正如您所看到的,结果略有不同。我只打印了这个:

myAge 不在 0 到 10 之间

我知道解决方案很简单,但不幸的是我无法解决它,因此它会打印:

myAge 不在 0 到 10 之间 myAge 在 30 到 39 之间或 myAge 是

以及。

请有人帮助我解决它,我真的很感激它!

Abh*_*r ツ 1

嵌套开关盒

var myAge = parseInt(prompt("Enter your age", 30), 10);

switch (true) {
  case myAge >= 0 && myAge <= 10:
    document.write("myAge is between 0 and 10<br/>");
  default:
    switch (true) {
      case (!(myAge >= 0 && myAge <= 10)):
        document.write("myAge is NOT between 0 and 10<br/>");
      default:
        switch (true) {
          case myAge >= 80 || myAge <= 10:
            document.write("myAge is 80 or above OR 10 or below<br/>");
          default:
            switch (true) {
              case (myAge >= 30 || myAge <= 39) || (myAge >= 80 && myAge <= 89):
                document.write("myAge is between 30 and 39 or myAge is " + "between 80 and 89");
            }
        }
    }
}
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理由:

  1. 由于您使用了一系列 if,而不是 if-else-if,这意味着我们不应该在 Switch 中使用带有 case 的break语句
  2. 如果我们不使用break,控件就会失败,因此不会检查连续情况的条件
  3. 强制条件检查的唯一方法是在 default 关键字后使用嵌套 Switch 语句!