我正在尝试将以下代码的输出转换为数据帧,其中列表是sfc数据帧,其中列包含简单的要素集合 - 每个观察一个多边形.
以下可重复示例和预期输出的输出:
# Reproducible example:
library(tidyverse)
library(sf)
library(magrittr)
# define radius for circle
radius <- 40
r <- units::set_units(radius, units::as_units("nmile"), mode = "standard")
%>%
units::set_units(units::as_units("m"), mode = "standard")
# Sample data:
df <- data.frame(var = c("abc", "bcd", "cab", "dba"),
lon = c(45,47,1, -109),
lat = c(7, 10, 59, 30))
# Creating simple features with sf:
df <- df %>% st_as_sf(coords = c("lon", "lat"), dim = "XY")
# Applying Coordinate reference system WGS84:
df <- df %>% st_set_crs(4326)
# create function for finding UTM zones
utm_prj4 <- function(x) {
coords <- cbind(x, st_coordinates(x))
long <- coords$X
lat <- coords$Y
zone <- if(lat >= 56 && lat < 64 && long >= 3 && long < 12){x <- 32} else
if(
lat >= 72 && lat < 84 && long >= 0 && long < 9) {x <- 31} else if(
lat >= 72 && lat < 84 && long >= 9 && long < 21) {x <- 33} else if(
lat >= 72 && lat < 84 && long >= 21 && long < 33) {x <- 35} else if(
lat >= 72 && lat < 84 && long >= 33 && long < 42) {x <- 37} else{
x <- (floor((long + 180)/6) %% 60) + 1
}
prj <- purrr::map2_chr(zone, lat, function(y, z){
if (z >= 0){
paste0("+proj=utm +zone=", y, " +datum=WGS84 +units=m +no_defs")
} else{
paste0("+proj=utm +zone=", y, " +south", " +datum=WGS84 +units=m
+no_defs")
}})
prj
}
# creates a list of data.frames, each with different crs
dfs <- map2(1:4, utm_prj4(df), function(x, y){
st_transform(df[x,], y)
})
df <- map(dfs, ~ st_buffer(., r))
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我试过as.data.frame但它不起作用.我尝试了data.frame(t(as.data.frame(df))并且它不起作用.
可重现示例的输出位于左侧:
您需要确保您的sf
对象具有相同的crs,否则您无法将它们的几何组合成一个sfc
(简单的特征列).一旦我们将它们转换成longlat
例如,我们就可以rbind
了.
df_ll = map(df, ~ st_transform(., 4326))
df_sf = do.call(rbind, df_ll)
## or using Reduce
df_sf = Reduce(rbind, df_ll)
## or using purrr version of reduce
df_sf = reduce(df_ll, rbind)
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