为什么spark在sql查询的末尾附加'WHERE 1 = 0'

sam*_*m N 5 apache-spark apache-spark-sql spark-dataframe

我正在尝试使用 Apache Spark 执行一个简单的 mysql 查询并创建一个数据框。但是由于某些原因,spark'WHERE 1=0'在我要执行的查询末尾追加并抛出异常声明'You have an error in your SQL syntax'.

val spark = SparkSession.builder.master("local[*]").appName("rddjoin"). getOrCreate()
 val mhost = "jdbc:mysql://localhost:3306/registry"
val mprop = new java.util.Properties
mprop.setProperty("driver", "com.mysql.jdbc.Driver")mprop.setProperty("user", "root")
mprop.setProperty("password", "root")
val q= """select id from loaded_item"""
val res=spark.read.jdbc(mhost,q,mprop)
res.show(10)
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例外如下:

18/02/16 17:53:49 INFO StateStoreCoordinatorRef: Registered StateStoreCoordinator endpoint
Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'select id from loaded_item WHERE 1=0' at line 1
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:62)
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
    at java.lang.reflect.Constructor.newInstance(Constructor.java:423)
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:425)
    at com.mysql.jdbc.Util.getInstance(Util.java:408)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:944)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3973)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3909)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2527)
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2680)
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2484)
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1858)
    at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:1966)
    at org.apache.spark.sql.execution.datasources.jdbc.JDBCRDD$.resolveTable(JDBCRDD.scala:62)
    at org.apache.spark.sql.execution.datasources.jdbc.JDBCRelation.<init>(JDBCRelation.scala:114)
    at org.apache.spark.sql.execution.datasources.jdbc.JdbcRelationProvider.createRelation(JdbcRelationProvider.scala:52)
    at org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:307)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:178)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:146)
    at org.apache.spark.sql.DataFrameReader.jdbc(DataFrameReader.scala:193)
    at GenerateReport$.main(GenerateReport.scala:46)
    at GenerateReport.main(GenerateReport.scala)
18/02/16 17:53:50 INFO SparkContext: Invoking stop() from shutdown hook
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wer*_*ner 6

您调用的第二个参数spark.read.jdbc不正确。您应该使用由架构限定的表名或具有别名的有效 SQL 查询,而不是指定 sql 查询。在您的情况下,这将是val q="registry.loaded_item". 如果您想提供附加参数(可能用于 where 语句),另一种选择是使用其他版本的DataframeReader.jdbc

顺便说一句:您看到奇怪的查询的原因WHERE 1=0是 Spark 试图在不加载任何实际数据的情况下推断您的数据框的架构。此查询保证永远不会提供任何结果,但 Spark 可以使用查询结果的元数据来获取架构信息。

  • 一点更正:第二个参数(`dbtable`)可以是*表名用架构限定*或*有效的`SQL`查询*如[此处](https://medium.com/@radek.strnad /tips-for-using-jdbc-in-apache-spark-sql-396ea7b2e3d3)。但是,如果是查询,则必须将其括在括号中并像这样使用别名`"(select id from registry.loaded_item) AS sql"` (4认同)