Netlogo - 在 n 个代理之间平均分配世界

fol*_*ra2 1 range netlogo

我正在 Netlogo 中创建一个检查模型,每个检查员负责 n 个补丁。也就是说,我需要将世界划分为每个检查员专属的区域。

我尝试使用设置范围(世界宽度*世界高度/检查员)^ 0.5

但它们的范围比预期要高,并且允许一名检查员“侵入”其他检查员的区域,这是不可取的。

Luk*_*e C 5

这种方法可能过于复杂,但可能会满足您的需要 - 它将世界分成甚至垂直的“领土”带。请注意,只有当世界的最小 xcor 为 0,并且世界宽度可被 的数量整除时,它才能正常工作inspectors- 否则一个检查员将拥有与其他检查员不同的检查区域。例如,使用此设置:

breed [ inspectors inspector ]
inspectors-own [ my-territory ]

to setup
  ca
  resize-world  0 29 0 29
  create-inspectors ninspectors [
    set my-territory nobody
  ]
  split
  reset-ticks
end
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制作列表来存储最小值和最大值xcor,然后使用它们来划分补丁以将其作为区域分配给不同的检查员。更多解释见评论:

to split 
  ; get a count of the inspectors
  let n count inspectors

  ; get section widths
  let n-xcor ( max-pxcor - min-pxcor ) / n

  ; build lists to define min-maxes of sections
  let n-min ( range min-pxcor max-pxcor n-xcor )
  let n-max lput ( max-pxcor + 1 ) n-min
  set n-max but-first n-max

  ; Foreach of the min-max pairs, set patches within 
  ; the min-max boundary be set to the territory of one
  ; of the inspectors that currently has no territory
  ( foreach n-min n-max [
    [ _min _max ] -> 
    set _min ceiling _min
    set _max ceiling _max
    let cur_inspector one-of inspectors with [ my-territory = nobody ]
    ask patches with [ pxcor >= _min and pxcor < _max ] [
      ask cur_inspector [
        ifelse my-territory = nobody [
          set my-territory myself
        ] [
          set my-territory ( patch-set my-territory myself )
        ]
      ]
      set pcolor ( [color] of cur_inspector ) - 2
    ]
  ]) 

  ; Move inspectors to their territory
  ask inspectors [
    setxy ( mean [pxcor] of my-territory ) ( mean [pycor] of my-territory )
    show my-territory
    pd
  ] 
end
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要检查它是否正常工作,您可以让检查员四处走动:

to go 
  ask inspectors [
    face one-of neighbors with [ member? self [my-territory] of myself ]
    fd 1
  ]
  tick
end
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