Qex*_*Qex 9 python yaml pyyaml
我有一个文件 *.yaml内容如下:
bugs_tree:
bug_1:
html_arch: filepath
moved_by: user1
moved_date: '2018-01-30'
sfx_id: '1'
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我想在节点下的这个文件中添加一个新的子元素 [bugs_tree]
我尝试执行此操作如下所示:
if __name__ == "__main__":
new_yaml_data_dict = {
'bug_2': {
'sfx_id': '2',
'moved_by': 'user2',
'moved_date': '2018-01-30',
'html_arch': 'filepath'
}
}
with open('bugs.yaml','r') as yamlfile:
cur_yaml = yaml.load(yamlfile)
cur_yaml.extend(new_yaml_data_dict)
print(cur_yaml)
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然后文件应该看起来:
bugs_tree:
bug_1:
html_arch: filepath
moved_by: username
moved_date: '2018-01-30'
sfx_id: '1234'
bug_2:
html_arch: filepath
moved_by: user2
moved_date: '2018-01-30'
sfx_id: '2'
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当我尝试执行.append()OR .extend()OR 时.insert()出现错误
cur_yaml.extend(new_yaml_data_dict)
AttributeError: 'dict' object has no attribute 'extend'
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如果您想更新文件,仅读取是不够的。您还需要再次写入该文件。像这样的事情会起作用:
with open('bugs.yaml','r') as yamlfile:
cur_yaml = yaml.safe_load(yamlfile) # Note the safe_load
cur_yaml['bugs_tree'].update(new_yaml_data_dict)
if cur_yaml:
with open('bugs.yaml','w') as yamlfile:
yaml.safe_dump(cur_yaml, yamlfile) # Also note the safe_dump
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我没有对此进行测试,但他的想法是使用read来读取文件并使用 write来写入文件。使用safe_load并safe_dump像Anthon所说的那样:
“绝对没有必要使用 load(),它被记录为不安全。请改用 safe_load()”
你需要使用update
cur_yaml.update(new_yaml_data_dict)
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结果代码
with open('bugs.yaml','r') as yamlfile:
cur_yaml = yaml.load(yamlfile)
cur_yaml.update(new_yaml_data_dict)
print(cur_yaml)
with open('bugs.yaml','w') as yamlfile:
yaml.safe_dump(cur_yaml, yamlfile) # Also note the safe_dump
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