今天=
today = datetime.datetime.now().strftime("%Y%m%d")
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90天前
DD = datetime.timedelta(days=-90)
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我今天如何获得 - DD或90天前?
小智 36
您应该能够从datetime对象中减去时间增量.
today = datetime.datetime.now()
DD = datetime.timedelta(days=90)
earlier = today - DD
earlier_str = earlier.strftime("%Y%m%d")
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bgp*_*ter 14
只需从日期时间中减去timedelta:
>>> import datetime
>>> today = datetime.datetime.today()
>>> DD = datetime.timedelta(days=90)
>>> today - DD
datetime.datetime(2010, 11, 3, 9, 56, 20, 924224)
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(或者如果你想像你那样使用负时间值,请添加它们:
>>> DD = datetime.timedelta(days=-90)
>>> today + DD
datetime.datetime(2010, 11, 3, 9, 56, 20, 924224)
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你需要减去timedelta(days=90):
from datetime import date, datetime, timedelta
today = datetime.now()
dd = today - timedelta(days=90)
print(dd)
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它应该打印 2010-11-03 15:04:42.289684.
小智 5
from datetime import date,timedelta
currentDay = date.today()
requestedDay = currentDay - timedelta(days=90)
print(requestedDay)
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希望它能解决。
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