Chrome 扩展：如何将消息从 content.js 发送到 popup.js - Page_Action

Question

铬 v64。

我想从 content.js 向 popup.js 发送消息。

我设法从 popup.js 向 content.js 发送消息。但如何以相反的方式做到这一点？我还下载了一个示例扩展，它也不起作用。

我必须添加特殊权限吗？我尝试了一次消息传递和长时间运行的消息通道。

权限：

 "permissions": [
    "background",
    "tabs",
    "activeTab",
    "storage",
    "webRequest",

内容.js

chrome.runtime.sendMessage({
    data: "mauzen"
}, function (response) {
   return true;
});
debugger;
var port = chrome.runtime.connect({
    name: "knockknock"
});
port.postMessage({
    joke: "Knock knock"
});
port.onMessage.addListener(function (msg) {
    debugger;
    if (msg.question == "Who's there?")
        port.postMessage({
            answer: "Madame"
        });
    else if (msg.question == "Madame who?")
        port.postMessage({
            answer: "Madame... Bovary"
        });
});

背景.js

chrome.runtime.onMessage.addListener(function (request, sender, sendResponse) {
    sendResponse({
        data: "background"
    });
    if (request.data === "success") {
        alert("success");
    } else {
        //alert(request.data);
    }
});

console.assert(port.name == "knockknock");
port.onMessage.addListener(function (msg) {
    if (msg.joke == "Knock knock")
        port.postMessage({
            question: "Who's there?"
        });
    else if (msg.answer == "Madame")
        port.postMessage({
            question: "Madame who?"
        });
    else {
        port.postMessage({
            question: "background"
        });
    }
});

弹出窗口.js

chrome.runtime.onMessage.addListener(function (message, sender, sendResponse) {
    sendResponse({
        data: "popup"
    });
    if (message.data === "success") {
        alert("success");
    } else {
        // alert(message.data);
    }
});

chrome.runtime.onConnect.addListener(function (port) {
    console.assert(port.name == "knockknock");
    port.onMessage.addListener(function (msg) {
        if (msg.joke == "Knock knock")
            port.postMessage({
                question: "Who's there?"
            });
        else if (msg.answer == "Madame")
            port.postMessage({
                question: "Madame who?"
            });
        else {
            port.postMessage({
                question: "popup"
            });
        }
    });
});

Answer 1

这是我发现的，测试了一下。

要将消息从 content.js脚本发送到您的弹出窗口，请执行以下操作：

 chrome.runtime.sendMessage({
                    data: "Hello popup, how are you"
                }, function (response) {
                    console.dir(response);
                });

并在您的 popup.js 中：

chrome.runtime.onMessage.addListener(function (message, sender, sendResponse) {
    sendResponse({
        data: "I am fine, thank you. How is life in the background?"
    }); 
});

从 content.js 发送到 popup.js 的消息只会在您的 Popup 处于活动状态（=打开）时收到

，即您单击工具栏中的 page_action (browser_action) 图标并出现弹出窗口，然后它是打开/活动的。只有这样，它才能发送和接收消息！

你可以这样测试

将以下脚本放入content.js：

 var timer = 0;
  var si = setInterval(() => {
            try {
               chrome.runtime.sendMessage({
                    data: "Hello popup, how are you"
                }, function (response) {
                    console.dir(response);
                });
                timer++;
                if (timer === 5) {
                    clearInterval(si);
                }
            } catch (error) {
                // debugger;
                console.log(error);
            }
        }, 2000);

并在您的 **popup.js 中：**

chrome.runtime.onMessage.addListener(function (message, sender, sendResponse) {
    alert("I am popup!");
    sendResponse({
        data: "I am fine, thank you. How is life in the background?"
    }); 
});

只要setInterval执行，你就可以点击你的扩展图标，打开弹出窗口，然后它会显示一个警报。