org.springframework.orm.hibernate3.HibernateQueryException - HibernateTemplate

Question

我遇到了HibernateTemplate的问题,我不知道我哪里出错了.我正在使用Hibernate3和Tomcat6.在我的DAO中,我有一些函数试图使用字符串查询数据库,它们似乎工作正常.像这样

public AppUser getUserByUserName(String username){
    HibernateTemplate template=new HibernateTemplate(sessionFactory);
    try{
        List<AppUser> appList = template.find(" from AppUser as au where au.username=?", username);
        tempUser = appList.get(0);  
        return tempUser;
    } catch(Exception e){
        System.out.println("Problem in AppUserDao--get byUsername: " + e.toString());
        return null;
    }
}

然而,当我尝试使用整数查询时.喜欢:

public List<AppUser> getAllMerchants(){
    HibernateTemplate template=new HibernateTemplate(sessionFactory);
    try{
        List<AppUser> appList = template.find(" from appuser as au where au.securityLevel!=?", 112);
        if(appList.size() > 0)
            return appList;
        else
            return null;
    } catch(Exception e){
        System.out.println("Problem in AppUserDao--getAllMerchants: " + e.toString());
        return null;
    }
}

我收到此错误:

org.springframework.orm.hibernate3.HibernateQueryException: appuser is not mapped [ from appuser as au where au.securityLevel!=?]; nested exception is org.hibernate.hql.ast.QuerySyntaxException: appuser is not mapped [ from appuser as au where au.securityLevel!=?]

我的实体似乎有必要的注释.由于它适用于第一个功能,我不明白为什么它不适用于第二个功能.

@Entity
@Table(name="appuser")
public class AppUser {
    private int id;
    private String username;
    private String password;
    private String firstName;
    private String secondName;
    private int state;
    private int securityLevel;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO, generator= "idSeq")
    @SequenceGenerator(name="idSeq",sequenceName="app_user_seq_id")
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public String getUsername() {
        return username;
    }
    public void setUsername(String username) {
        this.username = username;
    }

    @Column(name="password_2")
    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }
    public String getFirstName() {
        return firstName;
    }
    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }
    public String getSecondName() {
        return secondName;
    }
    public void setSecondName(String secondName) {
        this.secondName = secondName;
    }
    public int getState() {
        return state;
    }
    public void setState(int state) {
        this.state = state;
    }
    public int getSecurityLevel() {
        return securityLevel;
    }
    public void setSecurityLevel(int securityLevel) {
        this.securityLevel = securityLevel;
    }

}

Answer 1

看起来您的代码中有拼写错误.在第一个函数中,您在第二个"来自appuser"中使用"来自AppUser".尝试将第二个查询更改为"从AppUser".