我正在使用php和mysql,我突然得到了
mysql_data_seek()[function.mysql-data-seek]:偏移0对MySQL结果索引64无效(或查询数据未缓冲)
这是什么意思.
我不知道从哪里开始调试这个.
class dbResult {
private $result;
private $num_rows;
function __construct($result) {
$this->result = $result;
}
function result($type = 'object') {
@mysql_data_seek($this->result, 0);
if ($type == 'array')
return mysql_fetch_assoc($this->result);
if ($type == 'object') {
if ($this->num_rows() == 1) {
$data = new stdClass();
foreach (mysql_fetch_assoc($this->result) as $k => $v)
$data->$k = $v;
return $data;
}
if ($this->num_rows() > 1) {
$data = array();
while ($result = mysql_fetch_assoc($this->result)) {
$row = new stdClass();
foreach ($result as $k => $v)
$row->$k = $v;
$data[] = $row;
}
return $data;
}
return false;
}
}
function num_rows() {
return mysql_num_rows($this->result);
}
function num_fields() {
return mysql_num_fields($this->result);
}
}
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Sha*_*ngh 10
如果结果集为空, mysql_data_seek()则会失败E_WARNING.这就是我认为在你的情况下发生,因为在调用之前你没有检查结果集是否为空mysql_data_seek().
如果行数> = 1,请始终检查结果的行数,然后您可以安全地调用 mysql_data_seek()