将列表转换为序列以制作 sympy Polygon

Question

我想从点列表中制作一个 sympy Polygon。文档说它需要一系列点。我不知道如何转换。

from sympy import Point2D, Polygon

# this works
p1 = Polygon(Point2D(0,0), Point2D(1,0), Point2D(1,1), Point2D(0,1))
print(p1.area)

# this fails at the Polygon call
points=[]
points.append(Point2D(0,0))
points.append(Point2D(0,1))
points.append(Point2D(1,1))
points.append(Point2D(1,0))
t = tuple(points)
p = Polygon(t)

当它失败时，我得到这个

Traceback (most recent call last):
  File "t_polygon.py", line 14, in <module>
    p = Polygon(t)
  File "C:\Program Files (x86)\Python\Lib\site-packages\sympy\geometry\polygon.py", line 126, in __new__
    vertices = [Point(a, dim=2, **kwargs) for a in args]
  File "C:\Program Files (x86)\Python\Lib\site-packages\sympy\geometry\polygon.py", line 126, in <listcomp>
    vertices = [Point(a, dim=2, **kwargs) for a in args]
  File "C:\Program Files (x86)\Python\Lib\site-packages\sympy\geometry\point.py", line 157, in __new__
    raise ValueError('Nonzero coordinates cannot be removed.')
ValueError: Nonzero coordinates cannot be removed.

Answer 1

取而代之的是：

t = tuple(points)
p = Polygon(t)

你需要写：

t = tuple(points)
p = Polygon(*t)