如何解决 log() 在 r 中产生 NaN 的错误

S.A*_*gie 5 r

我正在尝试对我的用户定义分布进行蒙特卡罗模拟研究,并且我修改了我R在一篇文章中看到的另一个代码。我的R代码如下;

library(rootSolve)
library(Matrix)
library(bbmle)

alpha=4
beta=0.3
rho=2
lambda=0.5
theta=0.2

samp=1000
par1=c(alpha,beta,rho,lambda,theta)

####Define BXIIWG quantile
BXIIWG_quantile=function(alpha,beta,rho,lambda,theta,u){
  f=function(x){
  beta*x^alpha+lambda*log(1+x^rho)+log(1-u)
  }
  x=uniroot(f,c(0,100),tol=0.0001)$root
  return(x)
}

####Define BXIIWG log-likelihood
BXIIWG_neglogl=function(alpha,beta,rho,lambda,theta){
  -sum(log(alpha*beta*x^(alpha-1)*(1+x^rho)+rho*lambda*x^(rho-1)))+(lambda+1)*sum(log(1+x^rho))-n*log(1-theta)+beta*sum(x^alpha)+2*sum(log(1-theta*(1+x^rho)^(-lambda)*exp(-beta*x^alpha)))
}

####Define simulation process of BXIIWG
BXIIWG_simulation=function(size=c(25,50,100,200,400,800),samp,par1){
Mean=vector()
RMSE=vector()
Bias=vector()
for (iter_size in 1:length(size)){
coef1=matrix(NA,samp,5)
colnames(coef1)=c('alpha','beta','rho','lambda','theta')
for (nsamp in 1:samp){
tryCatch(
{
x1_BXIIWG=NULL
q=runif(size[iter_size],0,1)
x1=sapply(q,BXIIWG_quantile,
alpha=par1[1],beta=par1[2],rho=par1[3],lambda=par1[4],theta=par1[5])
###BXIIWG for x1
x1_BXIIWG<-mle2(BXIIWG_neglogl,
start=list(alpha=par1[1],beta=par1[2],rho=par1[3],lambda=par1[4],theta=par1[5]),
method="L-BFGS-B",data=list(x=x1),
lower=c(alpha=0,beta=0,rho=0,lambda=0,theta=0),
upper=c(alpha=Inf,beta=Inf,rho=Inf,lambda=Inf,theta=1),use.ginv=TRUE)
coef[nsamp,]=coef(x1_BXIIWG)
},error=function(e){}
)
}
Mean[length(size)*(0:4)+iter_size]=apply(coef1,2,mean,na.rm=TRUE)
RMSE[length(size)*(0:4)+iter_size]=apply((coef1-matrix(rep(par1,nsamp),
ncol=5,byrow=T))^2,2,function(x){sqrt(mean(x,na.rm=TRUE))})
  }
Bias-as.vector(sapply(1:5,function(x){Bias[(length(size)*(x-1)+1):
(length(size)*x)]=Mean[(length(size)*(x-1)+1):(length(size)*x)]-par1[x]}))
samplesize=as.vector(t(mapply(rep,size,5)))
return(cbind(samplesize,Mean,RMSE,Bias))
}
BXIIWGsim1<-BXIIWG_simulation(25,1000,par1)
Mean1<-BXIIWGsim1$Mean
RMSE1<-BXIIWGsim1$RMSE
Bias1<-BXIIWGsim1$Bias
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当我运行这些代码时,我得到了以下错误;

(1) In log(1 - theta) : NaNs produced

(2) In log(1 - theta * (1 + x^rho)^(-lambda) * exp(-beta * ... : NaNs produced

(3) No values of Mean,RMSE and Bias are displayed in console

拜托,我需要帮助来解决这些问题。谢谢你。

小智 4

Hi,log(x)由于负值而产生 NaN。
假设:x = c(1,2,3,-4,-5)
log(x):NaN已生成

解决方案:
1. 需要重新检查数据集。
2. 如果有一些负面条目,则尝试删除观察结果[再次取决于具体情况]。
3.使用abs()::abs(x)答。1,2,3,4,5