Dar*_*rio 2 php symfony-forms symfony symfony4
我是symfony和symfony形式的新手.
我有一个带有EntityType的表单,如下所示:
->add('customer', EntityType::class, [
'label' => 'Kunde: ',
'class' => Customer::class,
'choice_label' => 'Name',
'query_builder' => function(EntityRepository $er) {
return $er->createQueryBuilder('c')
->select('CONCAT(c.firstname, " ", c.surname) AS Name');
}
])
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但我现在得到一个错误/警告:
Warning: spl_object_hash() expects parameter 1 to be object, string given
客户实体:
/**
* @ORM\Entity(repositoryClass="App\Repository\CustomerRepository")
*/
class Customer
{
/**
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(type="integer")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="firstname", type="string", length=50, nullable=false)
*/
private $firstname;
/**
* @var string
*
* @ORM\Column(name="surname", type="string", length=50, nullable=false)
*/
private $surname;
...
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非常感谢您的时间和帮助.
Yos*_*shi 12
你也可以简单地使用回调 choice_label
例如:
->add('customer', EntityType::class, [
'label' => 'Kunde: ',
'class' => Customer::class,
'choice_label' => function (Customer $customer) {
return $customer->getFirstname() . ' ' . $customer->getSurname();
// or better, move this logic to Customer, and return:
// return $customer->getFullname();
},
])
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