Symfony4 Forms - 带有两个choice_label的EntityType

Dar*_*rio 2 php symfony-forms symfony symfony4

我是symfony和symfony形式的新手.

我有一个带有EntityType的表单,如下所示:

->add('customer', EntityType::class, [
    'label' => 'Kunde: ',
    'class' => Customer::class,
    'choice_label' => 'Name',
    'query_builder' => function(EntityRepository $er) {
        return $er->createQueryBuilder('c')
            ->select('CONCAT(c.firstname, " ", c.surname) AS Name');
    }
])
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但我现在得到一个错误/警告:

Warning: spl_object_hash() expects parameter 1 to be object, string given

在此输入图像描述


客户实体:

/**
 * @ORM\Entity(repositoryClass="App\Repository\CustomerRepository")
 */
class Customer
{
    /**
     * @ORM\Id
     * @ORM\GeneratedValue
     * @ORM\Column(type="integer")
     */
     private $id;

    /**
     * @var string
     *
     * @ORM\Column(name="firstname", type="string", length=50, nullable=false)
     */
    private $firstname;

    /**
     * @var string
     *
     * @ORM\Column(name="surname", type="string", length=50, nullable=false)
     */
    private $surname;

    ...
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非常感谢您的时间和帮助.

Yos*_*shi 12

你也可以简单地使用回调 choice_label

例如:

->add('customer', EntityType::class, [
    'label' => 'Kunde: ',
    'class' => Customer::class,
    'choice_label' => function (Customer $customer) {
        return $customer->getFirstname() . ' ' . $customer->getSurname();

        // or better, move this logic to Customer, and return:
        // return $customer->getFullname();
    },
])
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  • 非常感谢,工作完美. (2认同)