Ada*_*Dev 1705

搜索表:

SELECT      c.name  AS 'ColumnName'
            ,t.name AS 'TableName'
FROM        sys.columns c
JOIN        sys.tables  t   ON c.object_id = t.object_id
WHERE       c.name LIKE '%MyName%'
ORDER BY    TableName
            ,ColumnName;
Run Code Online (Sandbox Code Playgroud)

搜索表格和视图:

SELECT      COLUMN_NAME AS 'ColumnName'
            ,TABLE_NAME AS  'TableName'
FROM        INFORMATION_SCHEMA.COLUMNS
WHERE       COLUMN_NAME LIKE '%MyName%'
ORDER BY    TableName
            ,ColumnName;
Run Code Online (Sandbox Code Playgroud)

  • @Revious`INFORMATION_SCHEMA` [SQL Server中包含的视图符合INFORMATION_SCHEMA的ISO标准定义.](http://technet.microsoft.com/en-us/library/ms186778.aspx),`sys.columns`, `sys.tables`是Microsoft Sql Server特有的. (17认同)
  • 在选择列表中包含`TABLE_SCHEMA`可能会有所帮助.还是+1,因为这是一个很好的答案. (4认同)
  • 您能否如@user3185569 所评论的那样,将两者之间差异的解释添加到您的答案中? (2认同)
  • 第二个也适用于 SQL Server 2000,如果您碰巧必须使用它 (2认同)
  • 也得到一个表架构:SELECT c.name AS ColName, t.name AS TableName, SCHEMA_NAME(t.schema_id) AS SchemaName .... (2认同)

小智 297

我们还可以使用以下语法: -

select * from INFORMATION_SCHEMA.COLUMNS 
where COLUMN_NAME like '%clientid%' 
order by TABLE_NAME
Run Code Online (Sandbox Code Playgroud)

  • 这对我有用,而最佳答案没有(我正在使用MariaDB). (8认同)
  • 鉴于“ INFORMATION_SCHEMA”是[ANSI标准]的一部分,因此它可以在所有这些不同的数据库上运行并不奇怪(https://en.wikipedia.org/wiki/Information_schema) (2认同)

小智 153

SELECT Table_Name, Column_Name 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_CATALOG = 'YOUR_DATABASE'
AND COLUMN_NAME LIKE '%YOUR_COLUMN%'
Run Code Online (Sandbox Code Playgroud)
  • 就那么简单!!(SQL,PL/SQL)我一直用它来查找给定数据库(模式)中列名的所有实例.

  • 我经常复制和粘贴这个 SQL,谢谢@Todd_ECU (6认同)
  • 这确实应该是公认的答案。您不必执行连接,这比接受的答案容易得多 (3认同)

Fra*_*ers 82

select  
        s.[name]            'Schema',
        t.[name]            'Table',
        c.[name]            'Column',
        d.[name]            'Data Type',
        c.[max_length]      'Length',
        d.[max_length]      'Max Length',
        d.[precision]       'Precision',
        c.[is_identity]     'Is Id',
        c.[is_nullable]     'Is Nullable',
        c.[is_computed]     'Is Computed',
        d.[is_user_defined] 'Is UserDefined',
        t.[modify_date]     'Date Modified',
        t.[create_date]     'Date created'
from        sys.schemas s
inner join  sys.tables  t
on s.schema_id = t.schema_id
inner join  sys.columns c
on t.object_id = c.object_id
inner join  sys.types   d
on c.user_type_id = d.user_type_id
where c.name like '%ColumnName%'
Run Code Online (Sandbox Code Playgroud)

这里将为您提供有关模式,表和列的一些额外信息,您可能会或可能不会选择在where子句中使用额外条件进行过滤.例如,如果您只想查看必须添加值的字段

and c.is_nullable = 0
Run Code Online (Sandbox Code Playgroud)

您可以添加其他条件,我还以这种垂直方式添加了select子句中的列,因此可以根据您的需要轻松地重新排序,删除,重命名或添加其他条件.或者,您可以使用T.Name搜索表.它非常可定制.

请享用.

  • d。[max_length]似乎没用。c。[max_length]可能就是您的意思。但是仍然让我到那里来投票。 (3认同)
  • 您可以将其放在查询“ORDER BY t.name”的末尾 (2认同)
  • 用户要小心。上面的查询意味着访问“sys”对象,但这并不总是正确的。以我为例,该查询没有返回任何内容。相反,使用“INFORMATION_SCHEMA”就像一个魅力。 (2认同)

cic*_*chy 75

这应该工作:

SELECT name 
FROM sysobjects 
WHERE id IN ( SELECT id 
              FROM syscolumns 
              WHERE name like '%column_name%' )
Run Code Online (Sandbox Code Playgroud)

  • 我会使用`sys.tables`而不是`sysobjects`(从SQL Server 2005开始不推荐使用) (6认同)
  • 列名称'id'无效 (3认同)

Dwo*_*olk 61

如果您更多地使用第三方工具,那里有很多选项,例如:

如果您的数据库包含加密对象(视图,过程,函数),则这些非常方便,因为您无法使用系统表轻松搜索这些对象.


use*_*912 43

我不知道为什么这么多人建议加入sys.table with sys.columns 你只需使用下面的代码:

Select object_name(object_id) as TableName,* from SYS.columns where name LIKE '%MyName%'

要么

如果您还需要模式名称:

Select * from  INFORMATION_SCHEMA.COLUMNS
where COLUMN_NAME LIKE '%MyName%'
Run Code Online (Sandbox Code Playgroud)

  • 他们从 sys.tables 获取模式名称,也许这对您来说不是问题,但对很多人来说都是如此。 (2认同)

小智 39

如果您只想要表名,则可以运行:

select object_name(object_id) from sys.columns
where name like '%received_at%'
Run Code Online (Sandbox Code Playgroud)

如果你也想要Schema Name(在很多情况下,你会有很多不同的模式,除非你能记住数据库中的每个表以及它所属的位置,这可能很有用)运行:

select OBJECT_SCHEMA_NAME(object_id),object_name(object_id) from sys.columns
where name like '%received_at%'
Run Code Online (Sandbox Code Playgroud)

最后,如果你想要一个更好的格式(虽然这是代码(在我看来)变得太复杂,易于编写):

select concat(OBJECT_SCHEMA_NAME(object_id),'.',object_name(object_id)) from sys.columns
where name like '%received_at%'
Run Code Online (Sandbox Code Playgroud)

请注意,您还可以根据我的内容创建一个函数:

CREATE PROCEDURE usp_tablecheck
--Scan through all tables to identify all tables with columns that have the provided string
--Stephen B
@name nvarchar(200)
AS
SELECT CONCAT(OBJECT_SCHEMA_NAME(object_id),'.',object_name(object_id)) AS [Table Name], name AS [Column] FROM sys.columns
WHERE name LIKE CONCAT('%',@name,'%')
ORDER BY [Table Name] ASC, [Column] ASC
GO
Run Code Online (Sandbox Code Playgroud)

值得注意的是,2012年添加了concat功能.对于2008r2和更早版本,使用+来连接字符串.

自从我发布这个以来,我已经重新格式化了proc.它现在有点高级,但看起来更麻烦(但它在一个proc中,所以你永远不会看到它)并且它的格式更好.

此版本允许您将其置于管理数据库中,然后搜索任何数据库.更改的decleration @db'master'取其所需的默认数据库是(注:使用CONCAT()函数将与2012+除非你改变了字符串连接使用才有效+运营商).

CREATE PROCEDURE [dbo].[usp_tablecheck]
    --Scan through all tables to identify all tables in the specified database with columns that have the provided string
    --Stephen B
    @name nvarchar(200)
    ,@db nvarchar(200) = 'master'
AS
    DECLARE @sql nvarchar(4000) = CONCAT('
        SELECT concat(OBJECT_SCHEMA_NAME(col.object_id,DB_ID(''',@db,''')),''.'',object_name(col.object_id,DB_ID(''',@db,'''))) AS [Table Name]
            ,col.name AS [Column] 
        FROM ',@db,'.sys.columns col
        LEFT JOIN ',@db,'.sys.objects ob 
            ON ob.object_id = col.object_id
        WHERE 
            col.name LIKE CONCAT(''%'',''',@name,''',''%'') 
            AND ob.type =''U''
        ORDER BY [Table Name] ASC
            ,[Column] ASC')
    EXECUTE (@sql)
GO
Run Code Online (Sandbox Code Playgroud)


Yog*_*dra 28

这是你问题的答案

SELECT c.name AS ColumnName, t.name AS TableName
FROM sys.columns c
    JOIN sys.tables t ON c.object_id = t.object_id
WHERE c.name LIKE '%myName%';
Run Code Online (Sandbox Code Playgroud)


sha*_*hah 25

USE AdventureWorks

GO

SELECT t.name AS table_name, SCHEMA_NAME(schema_id) AS schema_name,
 c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%EmployeeID%'
ORDER BY schema_name, table_name; 
Run Code Online (Sandbox Code Playgroud)

它来自Pinal Sir Blog


Nei*_*ght 22

SELECT COLUMN_NAME, TABLE_NAME
  FROM INFORMATION_SCHEMA.COLUMNS    
 WHERE COLUMN_NAME LIKE '%myName%'
Run Code Online (Sandbox Code Playgroud)


Mun*_*var 22

您可以通过column_name过滤器从INFORMATION_SCHEMA.COLUMNS中找到它

Select DISTINCT TABLE_NAME as TableName,COLUMN_NAME as ColumnName
     From INFORMATION_SCHEMA.COLUMNS Where column_name like '%myname%'
Run Code Online (Sandbox Code Playgroud)


小智 20

SELECT  [TABLE_NAME] ,
        [INFORMATION_SCHEMA].COLUMNS.COLUMN_NAME
FROM    INFORMATION_SCHEMA.COLUMNS
WHERE   INFORMATION_SCHEMA.COLUMNS.COLUMN_NAME LIKE '%NAME%' ;
Run Code Online (Sandbox Code Playgroud)


Sha*_*que 16

以下查询将为您提供具有字段名称(如'%myName')的数据库的确切表名.

SELECT distinct(TABLE_NAME)
  FROM INFORMATION_SCHEMA.COLUMNS    
 WHERE COLUMN_NAME LIKE '%myName%'
Run Code Online (Sandbox Code Playgroud)


dev*_*014 15

在 MS SQL Server 数据库中,使用此查询获取包含输入文本的表和相应的列名称:

SELECT t.name AS tableName, c.name AS columnName 
FROM sys.tables as t 
INNER JOIN sys.columns AS c ON t.object_id=c.object_id 
WHERE c.name LIKE '%<your_search_string>%'
Run Code Online (Sandbox Code Playgroud)


小智 14

获取完整信息:列名,表名以及表的架构.

SELECT COLUMN_NAME, TABLE_NAME, TABLE_SCHEMA
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE COLUMN_NAME LIKE '%col_Name%'
Run Code Online (Sandbox Code Playgroud)


Rin*_*ary 14

它将返回 table_name 、 schema_name 、 column_name

SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c
ON t.object_id = c.object_id
WHERE c.name LIKE '%colName%'
ORDER BY schema_name,
table_name;
Run Code Online (Sandbox Code Playgroud)


Alz*_*Alz 12

我刚尝试过,这完美无缺

USE YourDatabseName
GO
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%YourColumnName%'
ORDER BY schema_name, table_name;
Run Code Online (Sandbox Code Playgroud)

只将YourDatbaseName更改为您的数据库,将YourcolumnName更改为您要查找的列名称,保持原样.

希望这有所帮助


Mar*_*ese 12

我想要一些不会让我的眼睛流血的表格 视图

询问

SELECT
    t.TABLE_TYPE AS [Type],
    c.TABLE_NAME AS [Object],
    c.COLUMN_NAME AS [Column]
FROM
    INFORMATION_SCHEMA.COLUMNS AS c
    LEFT JOIN INFORMATION_SCHEMA.TABLES AS t ON
        t.TABLE_CATALOG = c.TABLE_CATALOG AND 
        t.TABLE_SCHEMA = c.TABLE_SCHEMA AND
        t.TABLE_NAME = c.TABLE_NAME
WHERE
    c.COLUMN_NAME LIKE '%myName%'
ORDER BY
    [Type],
    [Object],
    [Column]
Run Code Online (Sandbox Code Playgroud)

结果

Type        Object   Column
----------------------------
BASE TABLE  Table1   myName1
BASE TABLE  Table2   myName2
VIEW        View1    myName1
VIEW        View2    myName2
Run Code Online (Sandbox Code Playgroud)


小智 10

      SELECT   TABLE_SCHEMA +'.'+ TABLE_NAME, COLUMN_NAME   
      FROM [yourdatabase].INFORMATION_SCHEMA.COLUMNS
      WHERE COLUMN_NAME LIKE '%myName%'
Run Code Online (Sandbox Code Playgroud)

这将为您提供需要查找的列的表名。


Sau*_*ana 9

这个简单的查询对我有用。

SELECT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_schema = 'schemaName'
AND column_name like '%model%';
Run Code Online (Sandbox Code Playgroud)


Mau*_*tti 8

DECLARE @columnName as varchar(100)
SET @columnName = 'ColumnName'

SELECT t.name AS Table, c.name AS Column,
ty.name AS Type, c.max_length AS Length
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
INNER JOIN sys.types ty ON c.system_type_id = ty.system_type_id
WHERE c.name LIKE @columnName
ORDER BY t.name, c.name
Run Code Online (Sandbox Code Playgroud)


Rai*_*der 7

我用它来达到同样的目的,它起作用了:

  select * from INFORMATION_SCHEMA.COLUMNS
  where TABLE_CATALOG= 'theDatabase'
  and COLUMN_NAME like 'theCol%'
Run Code Online (Sandbox Code Playgroud)


soh*_*ian 7

你可以试试这个查询:

USE AdventureWorks
GO
SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%myName%'
Run Code Online (Sandbox Code Playgroud)

  • 看起来非常类似于 https://blog.sqlauthority.com/2008/08/06/sql-server-query-to-find-column-from-all-tables-of-database/ 如果没有别的,可以帮助解释。 (2认同)

Dan*_*n B 6

希望这不是一个重复的答案,但我喜欢做的是在sql语句中生成一个sql语句,这将允许我搜索我正在寻找的值(而不仅仅是具有这些字段名称的表(因为它通常是然后我必须删除与我正在寻找的列名的id相关的任何信息):

  SELECT  'Select * from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'
Run Code Online (Sandbox Code Playgroud)

然后我可以复制并粘贴运行我的第一列"SQLToRun"...然后我将'Select*from'替换为'Delete from',它允许我删除对该给定ID的任何引用!将这些结果写入文件,这样你有它们以防万一.

注意****确保在运行删除语句之前消除任何bakup表...

  SELECT  'Delete from ' + t.name + ' where ' + c.name + ' = 148' AS SQLToRun
  FROM sys.columns c, c.name as ColName, t.name as TableName
  JOIN sys.tables t 
     ON c.object_id = t.object_id
  WHERE c.name LIKE '%ProjectID%'
Run Code Online (Sandbox Code Playgroud)


Ped*_*uki 6

SELECT t.name AS table_name, 
    SCHEMA_NAME(schema_id) AS schema_name,
    c.name AS column_name
FROM sys.tables AS t INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%Label%'
ORDER BY schema_name, table_name;
Run Code Online (Sandbox Code Playgroud)


小智 5

只是为了改进上面的答案,我还包括了视图,并将架构和表/视图连接在一起,使结果更加明显。

DECLARE @COLUMNNAME AS VARCHAR(100);

SET @COLUMNNAME = '%Absence%';

SELECT CASE
           WHEN [T].[NAME] IS NULL
           THEN 'View'
           WHEN [T].[NAME] = ''
           THEN 'View'
           ELSE 'Table'
       END AS [TYPE], '[' + [S].[NAME] + '].' + '[' + CASE
                                                          WHEN [T].[NAME] IS NULL
                                                          THEN [V].[NAME]
                                                          WHEN [T].[NAME] = ''
                                                          THEN [V].[NAME]
                                                          ELSE [T].[NAME]
                                                      END + ']' AS [TABLE], [C].[NAME] AS [COLUMN]
FROM [SYS].[SCHEMAS] AS [S] LEFT JOIN [SYS].[TABLES] AS [T] ON [S].SCHEMA_ID = [T].SCHEMA_ID
                            LEFT JOIN [SYS].[VIEWS] AS [V] ON [S].SCHEMA_ID = [V].SCHEMA_ID
                            INNER JOIN [SYS].[COLUMNS] AS [C] ON [T].OBJECT_ID = [C].OBJECT_ID
                                                                 OR
                                                                 [V].OBJECT_ID = [C].OBJECT_ID
                            INNER JOIN [SYS].[TYPES] AS [TY] ON [C].[SYSTEM_TYPE_ID] = [TY].[SYSTEM_TYPE_ID]
WHERE [C].[NAME] LIKE @COLUMNNAME
GROUP BY '[' + [S].[NAME] + '].' + '[' + CASE
                                             WHEN [T].[NAME] IS NULL
                                             THEN [V].[NAME]
                                             WHEN [T].[NAME] = ''
                                             THEN [V].[NAME]
                                             ELSE [T].[NAME]
                                         END + ']', [T].[NAME], [C].[NAME], [S].[NAME]
ORDER BY '[' + [S].[NAME] + '].' + '[' + CASE
                                             WHEN [T].[NAME] IS NULL
                                             THEN [V].[NAME]
                                             WHEN [T].[NAME] = ''
                                             THEN [V].[NAME]
                                             ELSE [T].[NAME]
                                         END + ']', CASE
                                                        WHEN [T].[NAME] IS NULL
                                                        THEN 'View'
                                                        WHEN [T].[NAME] = ''
                                                        THEN 'View'
                                                        ELSE 'Table'
                                                    END, [T].[NAME], [C].[NAME];
Run Code Online (Sandbox Code Playgroud)


小智 5

像oracle一样,你可以找到表格和列:

select table_name, column_name
from user_tab_columns 
where column_name 
like '%myname%';
Run Code Online (Sandbox Code Playgroud)


小智 5

Create table #yourcolumndetails(
DBaseName varchar(100), 
TableSchema varchar(50), 
TableName varchar(100),
ColumnName varchar(100), 
DataType varchar(100), 
CharMaxLength varchar(100))

EXEC sp_MSForEachDB @command1='USE [?];
    INSERT INTO #yourcolumndetails SELECT
    Table_Catalog
    ,Table_Schema
    ,Table_Name
    ,Column_Name
    ,Data_Type
    ,Character_Maximum_Length
    FROM INFORMATION_SCHEMA.COLUMNS
    WHERE COLUMN_NAME like ''origin'''

select * from #yourcolumndetails
Drop table #yourcolumndetails
Run Code Online (Sandbox Code Playgroud)


小智 5

要在 MS SQL Server 中查找包含指定名称列的所有表,可以查询系统目录视图。具体来说,您可以查询 sys.tables 和 sys.columns 视图。这是一个示例查询:

SELECT t.name AS table_name
FROM sys.tables t
JOIN sys.columns c ON t.object_id = c.object_id
WHERE c.name = 'column_name';
Run Code Online (Sandbox Code Playgroud)

替换column_name为您要搜索的列的名称。此查询根据 object_id 列连接 sys.tables 和 sys.columns 视图,并过滤结果以检索列名与指定值匹配的表名。

dbForge Studio for SQL Server中,您可以使用SQL编辑器来执行上述查询。它提供语法突出显示、代码完成和结果查看等功能,使高效编写和执行 SQL 查询变得更加容易。