使用python获取Google Playstore应用下载链接

Question

我想获得特定类别的每个应用程序的Playstore链接.

这是我尝试过的:

r = br.open("https://play.google.com/store/apps/category/ART_AND_DESIGN/collection/topselling_free")
html = r.read()
soup = bsoup(html)

urlslist = soup.findAll("a", { "class" : "card-click-target" })

fo = open('url.txt', 'w')

for url in urlslist:
        print "".join(["https://play.google.com",url])
        fo.write("".join(["https://play.google.com",url])+"\n")

fo.close()

但它不会返回任何东西.urlslist也没有填充.我试过不同的标签和类,例如.soup.findAll("div", { "class" : "title" }),但这也返回一个空白数组.

请指教.先感谢您.

Answer 1

你必须迭代:

soup.findAll("a",{"class":"card-click-target"})

然后提取href每个a标签的属性,

因此,请更改以下代码:

for url in urlslist:
    print "".join(["https://play.google.com",url])
    fo.write("".join(["https://play.google.com",url])+"\n")

至:

for a in urlslist:
    link = "https://play.google.com" + a['href']
    print(link)
    fo.write(link + "\n")