Dar*_*ett 2 modelica openmodelica dymola
我有一个本地模型,当我检查Dymola声称有35个变量和34个未知数时,而当我在OMEdit中检查完全相同的模型时,它在34/34平衡.在确定什么算作变量时,是否包括所有输入和输出?
以下是我的模型:
model HeatStorage
extends PentakomoPlant.Interfaces.StorageFluidHeat;
parameter SI.Diameter D = 18.667 "Diameter";
parameter SI.Height H = 20 "Height";
parameter Boolean enable_losses = false "= true enable thermal losses with environment"
parameter SI.CoefficientOfHeatTransfer alpha = 1 "Constant heat transfer coefficient with the ambient"
parameter Boolean use_L = false "= true to display level as output variable"
parameter Real L_start = 0 "Start value of level in %"
parameter SI.Temperature T_start = from_degC(300) "Start value of temperature"
parameter SI.Temperature T_max = from_degC(550) "Maximum tank temperature"
parameter SI.Temperature T_set = from_degC(300) "Tank Heater Temperature Set-Point"
parameter SI.Power W_max = 30e8 "Hot Tank Heater Capacity"
parameter SI.Efficiency e_ht = 0.99 "Tank Heater Efficiency"
SI.Volume V;
SI.Mass m;
Medium.BaseProperties medium;
SI.Area A;
SI.HeatFlowRate Q_losses;
Medium.ThermodynamicState state_i = Medium.setState_pTX(medium.p, T_start);
SI.Power W_net;
SI.Power W_loss;
Modelica.Blocks.Interfaces.RealOutput L if use_L "Tank level in %"
Modelica.Blocks.Interfaces.RealInput T_amb if enable_losses
Modelica.Blocks.Interfaces.RealInput Q_heater
SI.HeatFlowRate Q_PB "Heat Flow to PowerBlock";
SI.HeatFlowRate Q_desal "Heat Flow to Desalination";
protected
parameter SI.Volume V_t = H * pi * D ^ 2 / 4;
Modelica.Blocks.Interfaces.RealOutput L_internal;
initial equation
medium.h = Medium.specificEnthalpy(state_i);
m = Medium.density(state_i) * V_t;
equation
if use_L then
connect(L_internal, L);
end if;
if enable_losses then
connect(T_amb_internal, T_amb);
Q_losses = -0.939 * exp(to_degC(medium.T) * 0.005111) * 1000;//*5/7;
else
T_amb_internal = Medium.T_default;
Q_losses = 0;
end if;
fluid_a.p = medium.p;
fluid_b.p = medium.p;
fluid_a.h_outflow = medium.h;
fluid_b.h_outflow = medium.h;
der(m) = fluid_a.m_flow + fluid_b.m_flow;
m * der(medium.h) + der(m) * medium.h = Q_losses + Q_PB + Q_desal + W_net + fluid_a.m_flow * inStream(fluid_a.h_outflow) + fluid_b.m_flow * medium.h;
V = m / medium.d;
L_internal = 100 * (max(medium.T, T_set) - T_set) / (T_max - T_set);
A = 2 * pi * (D / 2) * H;
W_net = Q_heater;
W_loss = W_net / e_ht;
//PowerBlock
heat_PB.Q_flow = Q_PB;
heat_DS.Q_flow = Q_desal;
heat_PB.T = medium.T;
heat_DS.T = medium.T;
end HeatStorage;
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附:
partial model StorageFluidHeat
extends SolarTherm.Icons.StorageModel;
Modelica.Fluid.Interfaces.FluidPort_a fluid_a(redeclare package Medium = Medium)
Modelica.Fluid.Interfaces.FluidPort_b fluid_b(redeclare package Medium = Medium)
replaceable package Medium = SolarTherm.Media.MoltenSalt.MoltenSalt_base
constrainedby Modelica.Media.Interfaces.PartialMedium
"Medium in the component"
Modelica.Thermal.HeatTransfer.Interfaces.HeatPort_b heat_PB
Modelica.Thermal.HeatTransfer.Interfaces.HeatPort_b heat_DS
end StorageFluidHeat;
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并且(对于介质的基本属性):
redeclare model extends BaseProperties(final standardOrderComponents=true)
"Base properties of medium"
equation
d = rho_T(T);
h = state.h;
u = h - p/d;
MM = 0.091438;
R = 8.3144/MM;
state.p = p;
T = T_h(h);
end BaseProperties;
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我正在努力寻找额外变量的位置,或者为什么在使用Dymola/OMEdit时可能会有所不同.
我试过遵循ELmqvist关于平衡模型的建议,所以在计算变量时我会正确地假设(对于这个模型):
8 x专用类变量3 x输入2 x输出7 x中基数属性变量2 x 5 x流体端口变量2 x 2 x热端口变量
= 34个变量
我错过了什么吗?
该模型并未完成所有库以启用测试(假设其他媒体存在类似问题),因此这将是一个不完整的答案.
此外,似乎可以删除一些方程和变量以简化模型.
但该模型存在一些问题:
请注意,测试本地模型可能很棘手 - 您最好将其包含在测试电路中.
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