Django Rest框架和外部API

Keb*_*son 1 django django-rest-framework

我想从外部API(https://example.com/consumers)获取数据。我可以像这样构建urls.py吗?

url(r'^(?P<test.com/consumers)>[0-9]+)$/', views.get, name="get"),
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还是您还有其他好主意?

谢谢。

Tho*_*ang 8

我认为最好创建自己的url端点,该端点映射到向外部API发出请求的视图。

# urls.py
url(r'^external-api/$', external_api_view)

# views.py
import requests
import time
from rest_framework import status
from rest_framework.response import Response

MAX_RETRIES = 5  # Arbitrary number of times we want to try

def external_api_view(request):
    if request.method == "GET":
        attempt_num = 0  # keep track of how many times we've retried
        while attempt_num < MAX_RETRIES:
            r = requests.get("https://example.com/consumers", timeout=10)
            if r.status_code == 200:
                data = r.json()
                return Response(data, status=status.HTTP_200_OK)
            else:
                attempt_num += 1
                # You can probably use a logger to log the error here
                time.sleep(5)  # Wait for 5 seconds before re-trying
        return Response({"error": "Request failed"}, status=r.status_code)
    else:
        return Response({"error": "Method not allowed"}, status=status.HTTP_400_BAD_REQUEST)
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只是一个例子。您也可以将其作为基于类的视图来完成。