XML颜色用于矩形的弯曲边缘之外的区域

Question

我正在为RelativeLayout的背景制作一个矩形,并想知道如何使该矩形的圆角边缘之外的区域也变为darker_grey.目前,只有这个矩形的内部是darker_grey

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle" >
    <solid android:color="@android:color/darker_gray" />
    <stroke android:width="1dip" android:color="@android:color/black"/>
    <corners android:radius="20dp" />
</shape>

Answer 1

您可以通过切换到layer-listdrawable,并将形状分层到纯色上来实现,如下所示:

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item>
        <color android:color="@android:color/darker_gray" />
    </item>
    <item>
        <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle">
            <solid android:color="@android:color/darker_gray" />
            <stroke android:width="1dip" android:color="@android:color/black"/>
            <corners android:radius="20dp" />
        </shape>
    </item>
</layer-list>