gui*_*efd 18 regex validation angular
我需要验证密码输入表单字段的强度.
要求是:
- 至少一个小写字符
- 至少一个大写字符
- 至少一个数字
(无论顺序)
到目前为止我搜索和尝试的内容如下所示,结果不一致.它似乎验证了正则表达式验证的顺序.
我需要的是检查是否存在至少一个char"类型".
谢谢
import { Component } from '@angular/core';
import { FormBuilder, FormGroup, Validators } from '@angular/forms';
@Component({
selector: 'signup',
templateUrl: './signup.component.html',
styleUrls: ['./signup.component.scss']
})
export class SignupComponent {
form: FormGroup;
constructor() {
this.init();
}
init() {
this.form = this.fb.group({
name: ['', [Validators.required]],
email: ['', [Validators.required, Validators.email],
password: ['', [
Validators.required,
Validators.pattern('((?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{8,30})')
]]
});
}
}
Run Code Online (Sandbox Code Playgroud)
Des*_*ond 24
我使用Angular的内置模式验证器对此进行了尝试,并且能够提出以下检查:
特殊字符
password: [
'',
[
Validators.required,
Validators.pattern('(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[$@$!%*?&])[A-Za-z\d$@$!%*?&].{8,}')
]
]
Run Code Online (Sandbox Code Playgroud)我要补充一点,我绝不是一个正则表达式专家.对于与OP密切相关的案例,这对我来说简直是有用的.也许它会帮助别人.Mozilla的文档帮助解决了这个问题,特别是编写正则表达式模式部分.
gui*_*efd 14
我无法正确使用Validator Pattern,因此我创建了一个Custom Validator,并使用三个简单的regex验证密码字段字符串.
无论如何,我期待正确使用Angular Validator Pattern.
自定义验证器
// password.validator.ts
import { FormControl } from '@angular/forms';
export interface ValidationResult {
[key: string]: boolean;
}
export class PasswordValidator {
public static strong(control: FormControl): ValidationResult {
let hasNumber = /\d/.test(control.value);
let hasUpper = /[A-Z]/.test(control.value);
let hasLower = /[a-z]/.test(control.value);
// console.log('Num, Upp, Low', hasNumber, hasUpper, hasLower);
const valid = hasNumber && hasUpper && hasLower;
if (!valid) {
// return what´s not valid
return { strong: true };
}
return null;
}
}
Run Code Online (Sandbox Code Playgroud)
用我的自定义验证器替换了验证器模式
// signup.component.ts
import { Component } from '@angular/core';
import { FormBuilder, FormGroup, Validators } from '@angular/forms';
import { PasswordValidator } from 'validators/password.validator';
@Component({
selector: 'signup',
templateUrl: './signup.component.html',
styleUrls: ['./signup.component.scss']
})
export class SignupComponent {
form: FormGroup;
constructor() {
this.init();
}
init() {
this.form = this.fb.group({
name: ['', [Validators.required]],
email: ['', [Validators.required, Validators.email],
password: ['', [
Validators.required,
PasswordValidator.strong
]]
});
}
}
Run Code Online (Sandbox Code Playgroud)
下面的解决方案考虑到密码要求的参数可能是动态的
该方法动态生成模式字符串
passRequirement = {
passwordMinLowerCase: 1,
passwordMinNumber: 1,
passwordMinSymbol: 2,
passwordMinUpperCase: 1,
passwordMinCharacters: 8
};
pattern = [
`(?=([^a-z]*[a-z])\{${this.passRequirement.passwordMinLowerCase},\})`,
`(?=([^A-Z]*[A-Z])\{${this.passRequirement.passwordMinUpperCase},\})`,
`(?=([^0-9]*[0-9])\{${this.passRequirement.passwordMinNumber},\})`,
`(?=(\.\*[\$\@\$\!\%\*\?\&])\{${this.passRequirement.passwordMinSymbol},\})`,
`[A-Za-z\\d\$\@\$\!\%\*\?\&\.]{${
this.passRequirement.passwordMinCharacters
},}`
]
.map(item => item.toString())
.join("");
resetPwdForm = this.fb.group({
newpwdctrlname: ['Passwod1@@5', [Validators.required, Validators.pattern(this.pattern)]],
shownewpwdctrlname: ['', []],
rptpwdctrlname: ['', [Validators.required]]
});
constructor (private fb: FormBuilder) {}
Run Code Online (Sandbox Code Playgroud)
在 stackblitz 上查看此演示
如果您查看Validator.js,您会注意到您可以将字符串或正则表达式文字都传递给Validators.pattern。
正则表达式作为字符串文字传递
'\\d',定义空白模式请使用'\\s',定义反斜杠,请使用'\\\\'。正则表达式作为正则表达式文字传递
/\s+/)因此,您可以使用以下两者之一:
this.form = this.fb.group({
name: ['', [Validators.required]],
email: ['', [Validators.required, Validators.email],
password: ['', [
Validators.required,
Validators.pattern('(?=\\D*\\d)(?=[^a-z]*[a-z])(?=[^A-Z]*[A-Z]).{8,30}')
]]
});
Run Code Online (Sandbox Code Playgroud)
要么
this.form = this.fb.group({
name: ['', [Validators.required]],
email: ['', [Validators.required, Validators.email],
password: ['', [
Validators.required,
Validators.pattern(/^(?=\D*\d)(?=[^a-z]*[a-z])(?=[^A-Z]*[A-Z]).{8,30}$/)
]]
});
Run Code Online (Sandbox Code Playgroud)
正则表达式详细信息
请注意,我建议的模式更改仅是与对比原理相关的更改:
^ -字符串的开始(隐含在字符串正则表达式模式中)(?=\D*\d) -必须为1位数字(?=[^a-z]*[a-z]) -必须有1个小写ASCII字母(?=[^A-Z]*[A-Z]) -必须有1个大写ASCII字母 .{8,30} -除换行符以外的任何8至30个字符$ -字符串结尾(隐含在字符串正则表达式模式中)。| 归档时间: |
|
| 查看次数: |
24202 次 |
| 最近记录: |