YCF*_*F_L 4 java builder-pattern lombok
我用@Builder的龙目岛的项目,所以我认为有这样的例子:
@Builder
public class Client {
private @Getter @Setter Integer id;
private @Getter @Setter String name;
}
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这相当于:
public class Client {
private @Getter @Setter Integer id;
private @Getter @Setter String name;
public static class Builder {
private Integer id;
private String name;
private Builder() {
}
public Builder id(final Integer value) {
this.id = value;
return this;
}
public Builder name(final String value) {
this.name = value;
return this;
}
public Client build() {
return new Client(this);
}
}
public static Client.Builder builder() {
return new Client.Builder();
}
private Client(final Builder builder) {
this.id = builder.id;
this.name = builder.name;
}
}
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当我尝试一次性设置所有字段时没有问题:
public static void main(String[] args) {
Client client = Client.builder()
.id(123)
.name("name")
.build();
}
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输出:
Client{id=123, name=name}
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现在,考虑我想要多次拍摄.例如:
public static void main(String[] args) {
Client client = Client.builder()
.id(123)//<-------------------------- Set just the id
.build();
client = Client.builder()
.name("name")//<--------------------- Set name
.build();
}
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这在逻辑上返回null为id:
Client{id=null, name=name}
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通常,没有lombok,我通过在Builder类中添加一个采用相同对象的新构造函数来解决此问题:
public static class Builder {
// ...
public Builder(Client client) {
this.id = client.id;
this.name = client.name;
}
// ...
}
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然后我将我的对象传递给该构造函数:
Client client = Client.builder()
.id(123)
.build();
client = new Client.Builder(client)//<---------------- Like this
.name("name")
.build();
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这解决了我的问题,但我不能用lombok来解决它.有什么方法可以解决这个问题吗?
小智 5
您可以使用该toBuilder属性来执行此操作.
@Builder(toBuilder=true)
public class Client {
private @Getter @Setter Integer id;
private @Getter @Setter String name;
}
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然后你可以这样使用它
public void main(String[] args){
Client client = Client.builder()
.id(123)
.build();
client = client.toBuilder()
.name("name")
.build();
}
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